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hydrogenation of 2 butene

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From Wikipedia


2-Butene is an acyclic alkene with four carbon atoms. It is the simplest alkene to shown cis/trans-isomerism (also known as (E/Z)-isomerism); that is, it exists as two geometrical isomers cis-2-butene ((Z)-2-butene), shown at the right, and trans-2-butene ((E)-2-butene), not shown.

It is a petrochemical, produced by the catalytic cracking of crude oil. Its main uses are in the production of gasoline (petrol) and butadiene, although some 2-butene is also used to produce the solvent butanone via hydration to 2-butanol followed by oxidation.

The two isomers are extremely difficult to separate by distillation because of the proximity of their boiling points (4 °C for cis and 1 °C for trans). The more elongated trans-molecule which has a tougher job to get its tail free from the liquid has the higher boiling point, the more rounded cis isomer escapes easier, thus having a lower boiling piont. However, separation is unnecessary in most industrial settings, as both isomers behave similarly in most of the desired reactions. A typical industrial 2-butene mixture is 70% (Z)-2-butene (cis-isomer) and 30% (E)-2-butene (trans-isomer). Butane and 1-butene are common impurities, present at 1% or more in industrial mixtures, which also contain smaller amounts of isobutene, butadiene and butyne.


1-Butene is an organic compound and one of the isomers of butene. The formula is C4H8.


1-Butene is stable in itself but polymerizes exothermically. It is highly flammable and readily forms explosive mixtures with air. It is, however, incompatible with: Metal salts, fluorine and other halogens, nitrogen oxides, boron trifluoride, hydrohalic acids, and strong oxidizing agents.

From Yahoo Answers

Question:What is the expected major product arising from the reaction of 2-isopropyl-1-butene with hydrogen iodide? a. 1-iodo-2-isopropylbutane; via a Markovnikov addition b. 1,2-diiodo-2-isopropylbutane; via a Markovnikov addition c. 1-iodo-2-isopropylbutane; via an anti-Markovnikov addition d. 2-iodo-2-isopropylbutane; via an anti-Markovnikov addition e. 2-iodo-2-isopropylbutane; via a Markovnikov addition

Answers:e) 2-iodo-2-isopropylbutane; via a Markovnikov addition

Question:How many grams of hydrogen are needed to hydrogenate 65.0g 2-butene? Help with organic chemistry. Thanks!!

Answers:C4H8 + H2 -> C4H10 1 mole of the alkene uses 1 mole of hydrogen moles of butene in 65 g = 65 / 56.10 = 1.15 moles moles of hydrogen = 1.15 moles = 1.15 x 2.016 = 2.318 g

Question:What is the minimum amount of hydrogen gas required to completely hydrogenate 13000 grams of 2-butene? I'm guessing the 2-butene is CH3-CH=CH-CH3, but I don't know what else to do to help me solve this. Could someone help me out with additional steps, please? Thank you in advance!

Answers:The molar mass is about 56 g/mol (13,000 g)/(56 g/mol) = 232.14 mol There is one double bond per molecule, so you want to hydrogenate 232.24 mol of double bonds, for which you need 232.14 mol of H , or about 464.3 g of H : CH CH=CH CH + H CH CH CH CH

Question:I am drawing a blank as to how to find the answer to this. Any help is greatly appreciated!

Answers:C4H8 --> C4H10 The molecular weight of butene is 4 x 12 + 8 x 1 = 56g/mole 30.0g / 56g/mole = 0.536 moles 0f butene (all isomers of butene are C4H8) You need 2 moles of hydrogen (1 mole of H2) to hydrogenate each mole of butene, so you need 1.07 moles of H, so 1.07g

From Youtube

Free-Radical Addition of Hydrogen Bromide to 1-Butene (Ochem PLAY) :A play written, directed and produced by me! This video takes a radical rxn and turns it into a serious drama. The reaction: 1-Butene + Hydrogen Bromide ----(Peroxides & light/heat---- = 1-Bromobutane The mechanism: a)INITIATION step 1)dissociation of a peroxide into two alkoxy radicals step 2) Alkoxy radical takes a hydrogen away from the hydrogen bromide b) CHAIN PROPAGATION step 3)Addition of a bromine atom to the alkene step 4) Abstraction of a hydrogen atom from HBR by the free radical formed in step 3. ENJOY :)