#### • Class 11 Physics Demo

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#### • angle postulate

Question:I do not want answers, I want to be explained on how to do it. Please and thank you. < = a tiny triangle on my paper m
Question:I have two of these problems on my math homework and i don't know what they are or how to solve them. Im in the 11th grade and it's my Geometry homework Question 1) is DC= 5n-12 CE=3n+8 DE=52 and question 2) is GF=15x-9 FH=19x-1 GH=92

Answers:For #1 I am assuming that D and E are the endpoints of the line segment and that C is some point between them. The segment addition postulate simply states that DC (the distance from D to C) plus CE (the distance from C to E) is equal to DE (the distance from D to E) DC + CE = DE Now just plug in what you are given. DC = 5n - 12 so plug this in for DC and so on. (5n - 12) + (3n + 8) = 52 The idea here is to now solve for n and perhaps determine what the distances DC and CE are. 8n - 4 = 52 8n = 56 n = 7 So DC = 5n - 12 = 5(7) - 12 = 23 and CE = 3n + 8 = 3(7) + 8 = 29 The same sort of thing happens with #2.

Question:The question is: Let Q be in th interior of POR. Use the Angle Addition Postulate to solve for x. Find the measure of each angle. 14. m POQ = (x + 4) m QOR = (2x - 2) m POR = 26 I am not looking for the answer, I am just confused as to how to solve it. I have done problems using the Angle Addition Postulate before, except they were just angles and all I had to do was add two numbers together. So basically my question is how do I go about solving this? Thank you ahead of time. Nevermind haha I just figured it out myself! I realized I made a simple (but stupid as always) mistake when I was trying to figure it out. Instead, could you hellp with this problem? It contains fractions. *runs and hides* m POQ = (1/3x + 1/3) m QOR = (2x + 4/3) m POR = (5x - 1) If this is actually really simple, please tell me! Fractions always get me.