how to identify gold ore
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Answers:A little history lesson first there was this King who wanted to know if his crown was real gold or false gold so asked one of the great scientist of the time to see if he could solve the problem. For some weird reason the scientist was wearing the crown while in the tub he noticed the water level raised more with one gold than the fools gold so he jumped out of the tub and yelled (Eureka) supposedly that's how that saying started as to what I remember. So, to answer your question gold is more dense than fools gold so real gold will cause the water level to rise more than fools gold.
Answers:Classification: Magnetite A kind of iron oxide ore, the main ingredients are Fe3O4, and is the compounds of Fe2O3 and FeO, dark gray, the density about 5.15, with Fe72.4%, O 27.6%, and of magnetism, after a long period weathering it become hematite. Hematite Fe2O3, Is a kind of iron oxide ore, the main ingredients is Fe2O3, dark red, the density about 5.26, with Fe70%, O 30%, is the most important iron ore. Due to the its structural condition, it can be divided into many different categories, such as red hematite, SPEcularhematite, mica iron ore (Micaceous hematite), Red Ocher and so on. Limonite This is the ore containing ferric hydroxide. It is the common name of the two different structures of ore Goethite HFeO2 and LepidoCRocite FeO (OH), also the chemical formula of its main component was written as mFe2O3. nH2O, showing Khaki or brown color, containing Fe about 62%, 27% O,11% H2O , the density is about 3.6 to 4.0, mostly being attached to other iron ore. Siderite The carbonate of iron containing ore,its main ingredients is FeCO3, showing blue gray, with the density about 3.8. Most of this ore containing quite a lot of calcium and magnesium. Silicate Iron Such ore is a complex salt, there is no definite chemical formula, ingredients vary widely, usually with dark green, and the density about 3.8, very low iron content, is a poor iron ore. Iron sulfide This Kind of ore containing FeS2, with Fe only 46.6% while the content S reached 53.4%, appears sallow, the density about 4.95 ~ 5.10. Because this ore often contains many other precious metal such as Copper, Nickel , Zinc, Gold, Silver , so they are often used as raw materials for other metal smelting; also because it contains a large amount of sulfur, so is often used to distill the sulfur, thus rendered iron a by-product, and so it can not be classified as iron ore. Recommended Machinery: Spring Cone Crusher Impact Crusher Hammer Crusher Vertical Shaft Impact Crusher(FREE Sand making plant designing)
Answers:The best advice available here is to check the link below for a coin dealer specializing in US gold.
Answers:C is the answer (4.20 x 10 cm ) First determine how many grams of gold is equivalent to $100. You will need to converting troy ounce to grams. 1 troy ounce is exactly 31.1034768 grams http://en.wikipedia.org/wiki/Troy_ounce ($418.00 /toz) * (1 toz / 31.1035 grams) = $13.44/gram Then ($100) / ($13.44/gram) = 7.44 grams of gold to get $100 The the ore is just 0.22% Au, So divide grams of gold needed by this to get grams of ore needed. (7.44 grams of gold) / (0.0022) = 3382.29 grams of ore needed Finally, multibly by the density to get cm needed: (3382.29 grams of ore) / (8.0 g/ cm ) = 422 cm of ore