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# how to find the domain of a fraction

Question:g(x)= absolute value of x-1/ x-1 The denominator isn't in the absolute value part. How do you find the domain and range of it??

Answers:Domain = R\ {1} Range = { 1, -1}

Question:hello, I am have trouble solving f(t)=-11/(square root of t), I would like to find the domain and range of the function. sorry, i couldn't write the sign. please help me, I thought the domain is zero to positive infinity but what about the negative sign. I also need the range too. Thanks

Answers:Domain a) bottom of the fraction cannot be zero b) argument of square root has to be positive or zero Domain (0,infinity) Range a) bottom of fraction is positive Range (-infinity,0)

Question:I don't really understand how to find range. I think for the domain you set the equation equal to 0 and solve but I'm not positive. How would I find the domain and range of this problem? f(x) = sqr rt (4 - 2x) Thanks

Answers:for domain, it is basically the restrictions of what X can be. you would only set the equation to 0 if it was a fraction and the equation was on the bottom. and it shouldn't be asking you for range with that sort of problem. basically domain is the "x"s and range is the "y" values that fit in that function. Good luck oh so the domain for that function would be all reall numbers

Question:If the vertex is point (7,9) and the end points are points (6,8) and (8,8), how would you write the absolute value equation for this? Also, since there are endpoints to this absolute value, how would I describe or write the domain for this absolute value function. The absolute value function that I got for this function is y = - I(x- 7)I + 9 y equals neg (absolute value of x-7) plus nine

Answers:Your equation looks correct to me. The domain is the possible x values, namely 6 <= x <= 8