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how to find oxidizing agent

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From Yahoo Answers

Question:2N2H4 + N2O4 3N2 +4H2O How do you find the oxidizing agent and reducing agent? Can someone please explain?

Answers:N2O4 is the oxidising agent because it has given away its oxygen. The reducing agent is N2H4 because it has been oxidised by losing its hydrogen.

Question:Hello, Can anyone please tell me of a website where I can find the relative strengths of oxidizing and reducing agents TABLE? The table must include nitric acid.

Answers:Just google "Table of Electrode Potentials".

Question:When given 5 reactions, with their respective Eo values, how do I determine which reaction produces the strongest oxidizing agent? I know that an oxidizing agent gets reduced.

Answers:Usually we have the reduction standard potentials . To determine the strongest oxidizing agent we take which has the hightest value. F2 + 2e- >> 2 F- E = + 2.9 V Cl2 + 2e- >> 2 Cl- E = + 1.4 V F2 is the strongest oxidizing agent

Question:I have a question on my homework that asks me to indicate whether the following conversions require an oxidizing agent, reducing agent, or neither. CH4 -> H2CO3 PB^2+ -> PbSO4 Br2 -> HBrO2 How do you determine what they need? I have looked in my book and online at notes but nothing points me in the right direction so hopefully someone can help. Thanks.

Answers:1) OXIDIZING. cuz in the first one itsC= 4- and second its 2+ and O=2- and H=1+ in both (plus in organic chem you learn in you increase the numer of bonds to an atom has bonded to oxygen, it's oxidation--where the name comes from. if you reduce the number of bonds it has with oxygen then its reduction. CH4 has zero O bonds H2CO3 has 4 O bonds (there is a double bond). but oxidation numbers still work, and should be used 2)NEITHER. Pb is 2+ on both sides of the equation. SO4=2- you just have to know that polyatomic anion. S has 2 double bonded O's and 2 single bonded O's which each have a negative charge 3) OXIDIZING. Br2 = 0 aways does in it diatomic form. and in the second compound Br=3+ and O=2- and H=1+. O=2- and H=1+ is almost an always so just use them like that.

From Youtube

Oxidation Reduction Reactions :Clark College Tutoring and Writing Center tutor Joey Smokey introduces oxidation reduction (redox) reactions, explaining how reducing agents and oxidizing agents behave in a redox reaction.

Gummy Bear Oxidation :This demonstration shows how a strong oxidizing agent (Sodium Chlorate) can be used to oxidize a gummy bear totally in seconds. Dramatic demonstration