how to find oxidizing agent
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Answers:N2O4 is the oxidising agent because it has given away its oxygen. The reducing agent is N2H4 because it has been oxidised by losing its hydrogen.
Answers:Just google "Table of Electrode Potentials".
Answers:Usually we have the reduction standard potentials . To determine the strongest oxidizing agent we take which has the hightest value. F2 + 2e- >> 2 F- E = + 2.9 V Cl2 + 2e- >> 2 Cl- E = + 1.4 V F2 is the strongest oxidizing agent
Answers:1) OXIDIZING. cuz in the first one itsC= 4- and second its 2+ and O=2- and H=1+ in both (plus in organic chem you learn in you increase the numer of bonds to an atom has bonded to oxygen, it's oxidation--where the name comes from. if you reduce the number of bonds it has with oxygen then its reduction. CH4 has zero O bonds H2CO3 has 4 O bonds (there is a double bond). but oxidation numbers still work, and should be used 2)NEITHER. Pb is 2+ on both sides of the equation. SO4=2- you just have to know that polyatomic anion. S has 2 double bonded O's and 2 single bonded O's which each have a negative charge 3) OXIDIZING. Br2 = 0 aways does in it diatomic form. and in the second compound Br=3+ and O=2- and H=1+. O=2- and H=1+ is almost an always so just use them like that.