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# help to find a pattern in sequences

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Question:Write a rule for each sequence. Find the next 3 terms. 1.8, 4, 20, 26, 2.96, 84, 72, 60, 3.1, 4, 9, 16, 4.300, 150, 75, 37.5, 5.248, 246, 242, 236, 6.6, 12, 24, 48, Identify each sequence in exercises 1-6 as earthier arithmetic geometric or neither. 7. Exercise 1: 8. Exercise 2: 9. Exercise 3: 10. Exercise 4: 11. Execise 5 : 12. Ecxercise 6: Suppose you get an allowance starting at $0.05 a week. Each week there after,the amount you get doubles. 13. what kind of sequence is this? 14.during wich week your allowance be over 10$? Evalue each function for x = 0,1 , and 2 15. y = x to the second power -10 16. y = 3x = 2 17. y = x 3 solve each formula for n 18. 2n = 4xp 6 19. 3m n = 4s 20. r over n + 2 = p 21. t = 100 (n + 3 ) 22. pv/nr = t 23.8a + 2n = 6b 24.suppose you deposit $5,000 in a bank account that pays 4% interest compounded annually.How much will you have in your account at the end if 2 years? 25.Suppose you deposit$1,000 in an account earning 6% simple interest each year,Write a function rule that describes the total amount of money you will have after1 year, 26.The area of a trapezoid is found using the formula a = 1/2h (b1 + b2 ).Find the height of the trapezoid if the bases are 6 cm and 8 cm respectively and the area is 56 cm2.

Answers:only doing first part leaving you with #1 2. decrease by 12 3. add each term with odd number starting with 3 4. decrease by 1/2 5. subtract by multiples of 2 ex -2,-4 etc. 6. each number is doubled arithmetic means when the pattern of numbers rise or fall by same amount. geometric means each number is being added or multiplied to previous number to get the next number in sequence 1, 2, 4, 8, 16 1, next number 1+1=2 , 2+2=4, 4+4=8 or decrease by using a fraction or negative number you should be able to answer first part #24 formula A= P[1+ (r/n)]^(n*t) A=the amount of money after a certain amount of time P=the amount of money you start with r=interest rate---must change into a decimal number t= time in years n=number of times interest compound each year compounded annually n=1 " " quartery n=1/4 "" monthly n=12 The principal is the \$5000.00 r= 4/100 compound annually so n=1 t= 2 #25 is for you #26. simple solve for height plug in all the numbers 56 cm*cm = 1/2 * h (6cm +8cm) 2 * (56 cm*cm) = H (6cm + 8 cm) 2* 56(cm*cm)/ (6cm +8 cm) = H 2* 56(cm*cm)/ 14cm = H you do the rest

Question:What are these patterns and the next 3 terms: 0,7,26,63,124.... 1,4,16,25,36.... 5/-2,8/1,11/4,14/7,17/10... * These are Fractions * 1,5,13,26,45,71 1,2,6,24,120,720 1,1,2,3,5 I need Help!! If you can answer any Let me know Thanx so much : )

Answers:The last sequence is "Fibonacci's sequence", adding the two numbers before to get the next one, so 1,1,2,3,5,8,13,21 ...etc that's the only one I know sorry : ( I'm doing an assignment on Patterns/Sequences/Recursives at the moment and I'm about as stuck as you.

Question:This is just a fun, little bonus sheet we're doing in Algebra for Bonus...and I need help! My mom and I can't figure them out... There's a pattern and you need to find next 3 numbers in sequence 1.) 0, 2, 5, 10, 17, 28, 41, 58, __, __, __ 2.) 1, 2, 3, 7, 8, 10, 25, 26, 28, 79, __, __, __ 3.) 2, 3, 10, 12, 13, 20, 21, __, __, __ 4.) 2, 3, 4, 5, 6, 7, 8, 80, 9, 90, 10, __, __, __ 5.) 33, 34, 40, 41, 42, 43, 44, 100, 101, 102, __, __, __ 6.) S, H, I, U, X, N, T, D, E, R, E, __, __, __ HAVE FUN! I think the answer to number 2 is 80, 82, 190........agreed?

Answers:Based on a quick glance...here's what I have.. 1) prime number pattern last 3 should be 77, 100, 129 2) some equation around factorials like (n!/n)+1 but not quite 3) addition pattern of 1,7,2..1,7,1...1,7,0 ..so last- 22, 29, 29 Otherwise there is some pattern outside of base 10 numbers going on with it. Note that "10" is four in binary. 4) appears to have a magnitude factor kicking in or something significant with letters of the numbers...such as Two, Three, Four, Five, Six, Seven, Eight (but why not Eighteen after this one or Nineteen after Nine?) 6) alternating letters of sixteen and hundred to make the last 3 letters appropriately-- E,N,D Most I can offer at a quick glance. Good luck!

Question:How do I solve this: Find the next term of each sequence and explain: 2, 7, 24, 59, 118, 207... Alright, I've done these before. I know there's an equation or SOMETHING to solve this involving "n" that is used to find the value of any term in the sequence. I have no idea how to do these anymore. D: HELP. PLEASE. Feel free to email me, too. :] Thanks for the help!

Answers:Thanks for keeping me up with this :-) It's 02:00 am here! I tried to work with the pattern 6, 6, 6 after the iterated subtractions without success. Eventually I used the cubed hint of the first answerer: 1^3 - (-1) , 2^3 - 1 , 3^3 - 3 , 4^3 - 5 , 5^3 - 7 , 6^3 - 9 , 7^3 - 11 , ... So, the nth term starts with n^3 and the term you subtract? Aha! Arithmetic Series with a = -1, d = 2 and Tn = a+(n-1)d = -1 - 2 + 2n = 2n - 3 Your series' nth term thus: n^3 - (2n - 3). Goodnight.............zzzzzzzzz......