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#### • how to solve problems mathematics the 3 grade

Question:Alright well I'm really horrible with algebra but even worse, my word problem solving skills is atrocious! If anyone can help me solve these problems and show how you got them it would be amazingly appreciated! [Just having the answer will not help me] Please, I'm so desperate to understand this algebra so I can pass 1. Ted reached the 3-km mark of a race at 2:15pm and the 6-km mark at 2:24pm What is his running rate? 2. At one point Filbert Street, the steepest street in San Francisco, drops 63 feet over a horizontal distance of 200 feet. Find the road grade 3. Write a point slope equation for the line of slope -3 that contains the point (6,8) 4. There are approximately 292million Americans, and three quarters of them live in cities. How many urban Americans choose red as their favorite color? [There's a pie chart and the percentage of red is 4% which is the only relevant one needed for the question] [Also, because of rounding the total is slightly less than 100%] --For this question the answer comes out to 24,090,000 Americans but I don't understand how they got the answer =\

Question:A large painting in the style of Rubens is 3 ft longer than it is wide. If the wooden frame is 12 inches wide, the area of the picture and frame is 208 ft^2, find the dimensions of the painting. Interstate 70 west of Denver, Colorado, has a section posted as 6% grade. THis means that for a horizontal change of 100ft there is a 6ft vertical change. a) find the slope of this section of highway. b) on a highway with 6% grade what is the horizontal distance required to climb 250ft? c) A sign along the highways says 6& grade for the next 7 miles. Estimate how many feet of vertical change there are along those 7 miles (5280 ft = 1 mile). I'm not particularly good at word problems and I'm not exactly sure how to solve these, so could anyone help me? Thanks so much.

Answers:This is my homework too! But on the one about the highway I have part a and b done. The slope is the change which is repesented as the 6% grade. Therefore making the slope 0.06. So the answer to a is 0.06. For Part B. You calculated the horizontal distance by dividing 250 with 6 (vertical change) which gives you 41.66 then multiply this by 100 (horizontal change) which gives you 4166.7. Therefore making the answer to part b 4166.7

Question:1)A rectangle measures 15m by 10 m. How long is its diagonal? 2)A 2m ladder is placed against a wall. The foot of the ladder is 30 cm from the foot of the wall. How far up the wall does the ladder reach? 3)The length of a rectangle is 78 cm. This is 12 cm less than twice its width. What is the width of the rectangle? 4)The width of a rectangle is 5 cm longer than half its length. If the perimeter is 100cm, find the length, width and area of the rectangle.

Answers:1,2) It helps to draw the right triangle and recall the Pythagorean Theorem: a^2 + b^2 = c^2 3) Create a variable for the unknown, width. Then write an equation with that variable and solve for it. 4) Create a variable for the length, l. Then write an equation relating the width and length. Recall that the perimeter of a rectangle is given by perimeter = 2*width + 2*length. Also recall that the area of a rectange is given by area = length*width Go forth and solve, young mathematical grasshopper...

Question:Could someone please help me solve this math question? The sum of two numbers is 51. Twice the first plus 4 times the second is 128. What are the numbers? I seriously need help with math, as I AM really weak with math. Could you please tell me how to solve the question above step-by-step. It would really help! Thank You!!!!!

Answers:The sum of two numbers is 51. Twice the first plus 4 times the second is 128. What are the numbers? First you need to set the variables and write the equations. X = the value of the first number Y = the value of the second number First equation : x + y = 51 The sum (+) of the first and second number is (=) 51 Second equation : 2x + 4y = 128 Twice (2 times) the first number (x) plus (+) 4 times the second number (y) is (=) 128 Now that you have the two equations you need to solve for the variables. Set one equation equal to a variable. Lets do the first one: 1) x + y = 51 2) y = 51 - x subtract x from both sides Now that you have your equation set to one variable you can use that other equation to solve the numbers. First equation : y = 51 - x Second Equation : 2x + 4y = 128 Since we know y is equal to 51 - x (y = 51 - x) we can substitute that in for y. 2x + 4(51 - x) = 128 Substitute the (51 - x) for (y) Now solve the Equation for the variable since you only have one. 1) 2x + 4(51 - x) = 128 2) 2x + 204 - 4x = 128 Distribute the 4 to the 51 - x 3) -2x + 204 = 128 Combine the like terms 4) 204 = 128 + 2x Add 2x to both sides 5) 76 = 2x Subtract 128 from both sides 6) 38 = x divide by 2 Now that you know what x is we can solve for y. 1) x + y = 51 2) (38) + y = 51 Sub. in x 3) y = 13 Now we know what the numbers are X (first number) = 38 y (second number) = 13