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Question:Alright well I'm really horrible with algebra but even worse, my word problem solving skills is atrocious! If anyone can help me solve these problems and show how you got them it would be amazingly appreciated! [Just having the answer will not help me] Please, I'm so desperate to understand this algebra so I can pass 1. Ted reached the 3-km mark of a race at 2:15pm and the 6-km mark at 2:24pm What is his running rate? 2. At one point Filbert Street, the steepest street in San Francisco, drops 63 feet over a horizontal distance of 200 feet. Find the road grade 3. Write a point slope equation for the line of slope -3 that contains the point (6,8) 4. There are approximately 292million Americans, and three quarters of them live in cities. How many urban Americans choose red as their favorite color? [There's a pie chart and the percentage of red is 4% which is the only relevant one needed for the question] [Also, because of rounding the total is slightly less than 100%] --For this question the answer comes out to 24,090,000 Americans but I don't understand how they got the answer =\

Answers:1) Rate is the speed of running. In this case it would be km per hour. The distance (km) is 6 km minus 3 km (because you have times associated with those distances) 6 - 3 = 3 km. The time difference is 2:24pm - 2:15 pm or 9 minutes. Now to get the answer, you need to know the units that you want and set up the problem to find those units. So: km / hour = (km / minutes) X (minutes / hour) km / hour = 3 km / 9 minutes x 60 minutes / hour = 1/3 km / minute X 60 min / hour = 20 km per hour 2) See link for calculation of grade below. Grade is always vertical change divided by horizontal distance and usually expressed in percent. So it is 63 feet vertical divided by 200 feet horizontal & converted to percent. That is: 63 / 200 X 100 = 31.5% grade. 3) Point slope allows you to find the intercept from slope and a point. In the general equation Y = mX = b slope is m and intercept is b m is given in this problem as -3 Now solve the general equation for intercept: Y = mX + b or Y - mX = b Now substitute into your equation with the known point and slope: b = Y - mX b = 8 - (-3) x 6 b = 26 So the equation is Y = -3X + 26 4) There is a bit of information missing from this question. If 4% of all Americans choose red as their favorite color, then solve like this: a) What % of Americans live in an urban setting? If 3/4th live in a city then 3/4th of 292 million is 219 million. b) if 4% of all Americans choose red, then if there is no urban/country bias (which you don't know, by the way) Then 4% of 219 million is 8.76 million. That is quite different from your "answer" of about 24 million. It is possible that the answer that you were given is wrong. It is possible that they didn't give you enough information to answer the question.

Question:A large painting in the style of Rubens is 3 ft longer than it is wide. If the wooden frame is 12 inches wide, the area of the picture and frame is 208 ft^2, find the dimensions of the painting. Interstate 70 west of Denver, Colorado, has a section posted as 6% grade. THis means that for a horizontal change of 100ft there is a 6ft vertical change. a) find the slope of this section of highway. b) on a highway with 6% grade what is the horizontal distance required to climb 250ft? c) A sign along the highways says 6& grade for the next 7 miles. Estimate how many feet of vertical change there are along those 7 miles (5280 ft = 1 mile). I'm not particularly good at word problems and I'm not exactly sure how to solve these, so could anyone help me? Thanks so much.

Answers:This is my homework too! But on the one about the highway I have part a and b done. The slope is the change which is repesented as the 6% grade. Therefore making the slope 0.06. So the answer to a is 0.06. For Part B. You calculated the horizontal distance by dividing 250 with 6 (vertical change) which gives you 41.66 then multiply this by 100 (horizontal change) which gives you 4166.7. Therefore making the answer to part b 4166.7

Question:1)A rectangle measures 15m by 10 m. How long is its diagonal? 2)A 2m ladder is placed against a wall. The foot of the ladder is 30 cm from the foot of the wall. How far up the wall does the ladder reach? 3)The length of a rectangle is 78 cm. This is 12 cm less than twice its width. What is the width of the rectangle? 4)The width of a rectangle is 5 cm longer than half its length. If the perimeter is 100cm, find the length, width and area of the rectangle.

Answers:1,2) It helps to draw the right triangle and recall the Pythagorean Theorem: a^2 + b^2 = c^2 3) Create a variable for the unknown, width. Then write an equation with that variable and solve for it. 4) Create a variable for the length, l. Then write an equation relating the width and length. Recall that the perimeter of a rectangle is given by perimeter = 2*width + 2*length. Also recall that the area of a rectange is given by area = length*width Go forth and solve, young mathematical grasshopper...

Question:Could someone please help me solve this math question? The sum of two numbers is 51. Twice the first plus 4 times the second is 128. What are the numbers? I seriously need help with math, as I AM really weak with math. Could you please tell me how to solve the question above step-by-step. It would really help! Thank You!!!!!

Answers:The sum of two numbers is 51. Twice the first plus 4 times the second is 128. What are the numbers? First you need to set the variables and write the equations. X = the value of the first number Y = the value of the second number First equation : x + y = 51 The sum (+) of the first and second number is (=) 51 Second equation : 2x + 4y = 128 Twice (2 times) the first number (x) plus (+) 4 times the second number (y) is (=) 128 Now that you have the two equations you need to solve for the variables. Set one equation equal to a variable. Lets do the first one: 1) x + y = 51 2) y = 51 - x subtract x from both sides Now that you have your equation set to one variable you can use that other equation to solve the numbers. First equation : y = 51 - x Second Equation : 2x + 4y = 128 Since we know y is equal to 51 - x (y = 51 - x) we can substitute that in for y. 2x + 4(51 - x) = 128 Substitute the (51 - x) for (y) Now solve the Equation for the variable since you only have one. 1) 2x + 4(51 - x) = 128 2) 2x + 204 - 4x = 128 Distribute the 4 to the 51 - x 3) -2x + 204 = 128 Combine the like terms 4) 204 = 128 + 2x Add 2x to both sides 5) 76 = 2x Subtract 128 from both sides 6) 38 = x divide by 2 Now that you know what x is we can solve for y. 1) x + y = 51 2) (38) + y = 51 Sub. in x 3) y = 13 Now we know what the numbers are X (first number) = 38 y (second number) = 13

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Two Questions to Ask to Solve Arithmetic Word Problems :Solving an arithmetic word problem is achieved by understanding the problem and deciding what to do: to add, subtract, multiply, or divide. Two questions about the problem accomplish those goals: (1) What is happening, combining or separating? (2) How is it happening, just or neatly (by or into 2s, 3s, 4s, )? If the answers are combining and just, the problem is an addition problem. If separating and just, a subtraction problem. If combining and neatly, a multiplication problem, and if separating and neatly, a division problem. Go toMOVE IT Math on the web @ moveitmaththesource.com for lessons using Motley and mates to teach solving arithmetic word problems in elementary school math. The site is full of great basic math lessons that are effective with ALL children, including those who dont know what they ought to know by now and those who need enrichment. Please give us a chance to help you boost grades, increase test scores, and improve attitudes. EVERYONE can learn and like math. We are new to the web but have been making that happen for more than 35 years!

Grade 1 & 3 Morphological Problem-Solving :Watch as Ryan (Grade 1) and Jack (Grade 3) practice presenting the word matrix and word sums their groups built. They are preparing to present their knowledge to the Grade 4/5 class. Note how the same content can be studied by Grade 1 and Grade 3 students, but the older students are able to take that content further, and explain it more independently.