Your shopping cart is empty!
Explore Related Concepts


galileo acceleration due gravity
Best Results From Yahoo Answers Youtube
From Yahoo Answers
Question:
Answers:Galileo Galilei performed experiments with wooden balls rolling down a highly polished inclined plane to determine that gravitational acceleration was independent of mass. There's a story that he did it by dropping various weights off the Leaning Tower of Pisa, but that's almost certainly apocryphal.
Answers:Galileo Galilei performed experiments with wooden balls rolling down a highly polished inclined plane to determine that gravitational acceleration was independent of mass. There's a story that he did it by dropping various weights off the Leaning Tower of Pisa, but that's almost certainly apocryphal.
Question:What kind of information is indicated by a graph of acceleration due to gravity versus ball's mass if the slope of the curve is zero?
Answers:It is indicating that inertial mass and gravitational mass are the same property of matter.
Answers:It is indicating that inertial mass and gravitational mass are the same property of matter.
Question:How can I measure the acceleration due to gravity by using a meter stick, stopwatch, and rubber ball? Also, what equations shoud I use?
Answers:For this particular example, no calculus is needed. However, you will need the equation of motion for a falling object: y(t)=y0+vy0*t+(1/2)*a*t^2 where y0 is the starting height, vy0 is the initial velocity, a is the acceleration acting on the object, and t is the time elapsed. If we drop the ball from rest vy0=0, so we're left with y(t)=y0+(1/2)*a*t^2. If we start the stopwatch as soon as we drop the ball and stop the stopwatch as soon as the ball hits the ground and t seconds have elapsed, y(t)=0. We're left with 0=y0+(1/2)*a*t^2 We want to find a, so through the use of some algebra, we can perform the following steps: 0=y0+(1/2)*a*t^2 y0=(1/2)*a*t^2 2*y0=a*t^2 (2*y0)/(t^2)=a < this is what we want! All we need to do to measure the acceleration due to gravity is to drop a ball from a starting height y0, time how long it takes to strike the ground, and then input the starting height and time into the above equation. The acceleration due to gravity is often written as "g", so as to differentiate it from other sorts of accelerations that act on an object. For objects near the surface of the earth, g is approximately 9.8 [m/s^2].
Answers:For this particular example, no calculus is needed. However, you will need the equation of motion for a falling object: y(t)=y0+vy0*t+(1/2)*a*t^2 where y0 is the starting height, vy0 is the initial velocity, a is the acceleration acting on the object, and t is the time elapsed. If we drop the ball from rest vy0=0, so we're left with y(t)=y0+(1/2)*a*t^2. If we start the stopwatch as soon as we drop the ball and stop the stopwatch as soon as the ball hits the ground and t seconds have elapsed, y(t)=0. We're left with 0=y0+(1/2)*a*t^2 We want to find a, so through the use of some algebra, we can perform the following steps: 0=y0+(1/2)*a*t^2 y0=(1/2)*a*t^2 2*y0=a*t^2 (2*y0)/(t^2)=a < this is what we want! All we need to do to measure the acceleration due to gravity is to drop a ball from a starting height y0, time how long it takes to strike the ground, and then input the starting height and time into the above equation. The acceleration due to gravity is often written as "g", so as to differentiate it from other sorts of accelerations that act on an object. For objects near the surface of the earth, g is approximately 9.8 [m/s^2].
Question:How would you find the acceleration due to gravity at the surface of a planet if you're given:
a) mass = 1 kg
b) a graph of graviational potential energy vs. height above the surface of the planet?
Answers:POTENTIAL ENERGY IS A POINT FUNCTION defined as negative of work done by conservative force. Here conservative force is gravitational force given by mass * acceleration due to gravity 1 * a (say) a newton. If ground level is taken as zero potential then, at height h then gravitation force would have done work equal to (a) . (h)moving it to height h (Negative because displacement and force are in opposite directions and cos 180 = 1) Potential energy at height h would be = W =  (ah) =ah. at any height if potential energy is known then a can be calculated using math.... (here mass = 1. So the force is equal to acceleration in magnitude) Thus u dont need the full graph rather only a single pt is enough
Answers:POTENTIAL ENERGY IS A POINT FUNCTION defined as negative of work done by conservative force. Here conservative force is gravitational force given by mass * acceleration due to gravity 1 * a (say) a newton. If ground level is taken as zero potential then, at height h then gravitation force would have done work equal to (a) . (h)moving it to height h (Negative because displacement and force are in opposite directions and cos 180 = 1) Potential energy at height h would be = W =  (ah) =ah. at any height if potential energy is known then a can be calculated using math.... (here mass = 1. So the force is equal to acceleration in magnitude) Thus u dont need the full graph rather only a single pt is enough
From Youtube
Acceleration due to Gravity :This educational video is brought to you by Manipal K12 Technologies formerly Edurite Technologies a leading provider of educational content and learning solutions. This video talks about acceleration due to gravity and its values for calculations.
Acceleration Due to Gravity :In this video, I discuss the solution for a two step simple gravity acceleration problem www.mrlovescience.com