#### • Class 11 Physics Demo

Explore Related Concepts

# find zeros of a function calculator

Question:Any help appreciated.

Answers:hit the top left button: y=, then type 7x + 4 into it, then hit the top right button, graph, then hit trace, and move to the left and right until x is equal to zero (you'll know because it shows the coordinates on the bottom)

Question:The directions say find the zeros of this function: x^3+6^2+12x+8 I was taught to find the zeros by either using a graphing calculator, or factoring, then setting each factor to zero..but none of these work. Help, please?

Answers:try writing it as a factor:) (x+a)(x^2 + bx + c) = 0 x^3 + ax^2 +bx^2 + abx + cx + ca = 0 x^3 + (a+b)x^2 + (ab+c)x + ca = 0 here: x^3+6^2+12x+8 ca=8 ab+c = 12 a+b = 6 c= 4,a=2, b =4 x^3+6^2+12x+8 (x+2)(x^2 + 4x + 4) = (x+2)(x+2)(x+2) so with x^3+6^2+12x+8 = 0 (x+2)(x+2)(x+2) = 0 x= -2

Question:HELP! the directions say: "Find a real zero, to the nearest tenth, between the given values. y=x^3 + 2x^2 - 5x + 1; 1 and 2" i don't understand what it's asking or how to do it. oh btw, no graphing calculator -_- any other way to do it?

Answers:Get out a graphing calculator. Then hit "Y=". Then put in the equation above. Then, hit GRAPH. Then, hit ZOOM, then select option two, hit enter, then hit enter again to zoom in. Then, find where the line hits the x axis between one and two. Then, hit 2nd TRACE (CALC), and hit option two, ZERO. Then, using the arrow keys, select a place on the line to the left of the zero you are looking at, and hit ENTER. Then select a place to the right of the place where the line hits zero and hit ENTER again. Then, select about where the line hits zero, then hit ENTER again. At the bottom of your graph, you should see something like X=.22187616, and Y=0. Therefore, your answer, rounded to the nearest tenth, would be 0.2. Hope that helped.

Question:Help on this please f(x)=6x^4-5x^3-12x^2+5x+6, given that x=1 & x=-1 Need to find the other zeros

Answers:If you know how to use synthetic division, then you're set. synthetically divide x = 1 in, to get (x - 1) (some degree 3 equation) and then synthetically divide x = -1, to get (x - 1) (x + 1) (some quadratic equation) and then you can factor the quadratic equation. If you don't know how to synthetically divide, check out: http://www.purplemath.com/modules/synthdiv.htm :)