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# find the measure of angle abc

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Question:Ray BD bisects angle ABC. Find the measure of angle ABC if the measure of angle ABD is represented by 7x 2 and the measure of angle DBC is represented by 5x + 10.

Answers:Ray BD bisects angle ABC. Find the measure of angle ABC if the measure of angle ABD is represented by 7x 2 and the measure of angle DBC is represented by 5x + 10. 7x-2=5x+10 2x=12 x=6 5x+10=40 angle ABC=80

Question:Given: Segment BH is the angle bisector of angle ABC. The measure of angle ABC = 105. Find the value of x. http://i167.photobucket.com/albums/u142/XOJustaGurlOX/15.jpg

Question:In each Triangle ABC, find the measures for angle B and angle C that satisfy the given conditions. Draw diagrams to help you decide whether two triangles are possible. Remember that a triangle can have only one obtuse angle. 1. m angle A - 62 , a = 30, and b = 32 2. m angle A - 16 , a = 12, and b = 37.5 3. m angle A = 48 , a = 93, and b = 125 4. m angle A = 112 , a = 16.5, and b =5.4 5. m angle A = 23.6 , a = 9.8, and b = 17 6. m angle A = 155 , a = 12.5, and b = 8.4

Answers:Let's see... I will assume that side a is opposite angle A, side b is opposite angle B, and side c is opposite angle C. Hmm... For these problems, I'd use the Law of Cosines and the Law of Sines. Law of Cosines: c^2 = a^2+b^2-2ab cos C Law of Sines: sin A/a = sin B/b = sin C/c In each one of these problems, we have a, b and angle A. We can rewrite the Law of Cosines so that it reads: a^2 = b^2+ c^2 - 2bc cos A. Rewriting this as a quadratic would give: c^2 -(2b cos A)c + (a^2+b^2) = 0. If you use the quadratic formula, you'll have your solution(s) for c. The number of positive solutions determines the number of possible triangles that can be made with the given information (i.e., 1 or 2). Any less, and the triangle is impossible. Once you have side c solved for, you can then use the Law of Sines to find angle C: sin C = c/a * sin A. Using the inverse of sine on both sides will give you a value for C. 180 - A - C = B (since, for every triangle ABC, A+B+C=180). This will probably involve a lot of tedious work; however, if you have no diagram (like myself), this is the way to do it.

Question:Find the measure of angle DBC. 19 76 104 180 2-Angle ABC is a straight angle. The measure of angle ABD=6x-5 and the measure of angle DBC=2x+1. Find the measure of angle ABD. 23 47 121 133 3-Ray SU bisects angle RST. The measure of angle RSU=6x-3 and the measure of angle UST=5x+4. Find the measure of RSU. 7 39 41 78 4-Ray SU bisects angle RST. The measure of angle RSU=3x-1, the measure of angle UST=2x+13 and the measure of angle RST=6x-2. Find x. 12 14 41 82 5-Use the information from the previous question to find the measure of angle RSU. 12 14 41 82 Really could use some help, I don't have a book for any help,so I'm going for yahoo!! cause yall are the best!=)

Answers:1. ABD + DBC = ABC 4x + 5x + 9 = 180 9x = 171 x = 19 DBC = 5x + 9 = 95 + 9 = 104 ------- option c 2.ABD + DBC = ABC 6x 5 + 2x + 1 = 180 8x = 184 x = 23 ABD = 6x 5 = 133 ------- option d 3-Ray SU bisects angle RST. The measure of angle RSU=6x-3 and the measure of angle UST=5x+4. Find the measure of RSU. RST = RSU + UST RSU = UST 6x 3 = 5x + 4 x = 7 RSU = 42 3 = 39 -------- option b 4 RSU = 3x-1 = UST=2x+13 3x 1 = 2x + 13 x = 14 --------- option b 5. RSU = 3x 1 = 42 1 = 41 --------- option c --------