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# find domain and range of equation

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Question:Know how to plot points to find Domain & Range. Now need to learn how to find both D: and R: algebraically when dealing with radical equations. Know that whatever is under the radical must be > or = to 0. Also was told that whatever sign is on the constant under the radical, the Domain will be that number with the opposite sign. Doesn't seem to work though. Then was told that whatever number is outside the radical is the Range. (If no constant outside radical, then Range is (0, _) --- with the lowest value appearing first. Can anyone explain the procedures for finding Domain & Range algebraically when dealing with radicals? Have several problems to do, but please use this one to explain : g (x) = sq.rt. of x (under radical) + 2 (not under radical) Thanks!

Answers:I can't say I understand what you were told. The domain is the set of points that the function is defined for. If you aren't told the domain, then it is assumed that it is all values for which the expression makes sense. (This is not a requirement: I can define a function to have whatever domain I want, but I have to expressly state it.) For your g, the expression is defined for x >= 0, so that's the domain. The range is the set of values that the function takes on. As x goes from 0 to infinity, the sqrt of x covers the same set. But, g is sqrt(x) + 2, so g can take on any value >= 2, and that's its range.

Question:I don't really understand how to find range. I think for the domain you set the equation equal to 0 and solve but I'm not positive. How would I find the domain and range of this problem? f(x) = sqr rt (4 - 2x) Thanks

Answers:for domain, it is basically the restrictions of what X can be. you would only set the equation to 0 if it was a fraction and the equation was on the bottom. and it shouldn't be asking you for range with that sort of problem. basically domain is the "x"s and range is the "y" values that fit in that function. Good luck oh so the domain for that function would be all reall numbers

Question:i have no clue how to do this (well almost...) i've looked in the book adn online and can't find anything : identify the domain and range of the function in this situation the function is y= -16t^2 + 100 there is a graph the y axis goes to 120 by a scale of 20 and the x axis goes to 3 by a scale of .5 pls help! ps- 16t^2 means 16 times t squared also PLEASE can u explain to me how to find the domain and range?

Answers:y = -16t^2 + 100 When you give a function a domain or range, you are actually doing the following: Domain is the x-value bound in which the function can exist. Just by looking at the graph, you know that you can "plug in" any value of x and still get a y-coordinate to go along with it, so the domain is X R (or all real values of x are defined). The range represents what values the function can take on. By looking at your function, it is obvious that not all y-values can be defined. For your equation, find your y-intercept, which is in this case 100. Thus, cause it is a "upside-down" parabola, there cannot be values of y greater than y=100. Thus, your range is y 100. [Answer: see above]

Question:i have this math problem y=lxl and i have to find the range of it. The multiple choice are A:All Real Numbers B:yly < or equal to 0 C:xlx > or equal to 0 D: yly < or equal to 0 can you tell me how to find the range of this and how to find the domain of other equations like this..i am os confused and cannot understand this What is the answer to this problem!!!!!!! y= lxl

Answers:The domain is the set of all real numbers, as any real number can be plugged into x. The range is the set of all real numbers greater than or equal to zero, and |x| cannot be a negative number. Domain: R Range: R-(- ,0)