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definition of uniformly accelerated motion
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Question:Please give me the definition of the uniformly accelerated linear motion. Thanks.
Answers:Motion implies momentum, which implies velocity. Linear implies a straight line. Accelerating implies changing velocity. And uniform implies constancy. So, when a body moves in a straight line and accelerates at a constant rate, the body is said to have an uniformly accelerated linear motion.
Answers:Motion implies momentum, which implies velocity. Linear implies a straight line. Accelerating implies changing velocity. And uniform implies constancy. So, when a body moves in a straight line and accelerates at a constant rate, the body is said to have an uniformly accelerated linear motion.
Question:1. batman is sitting in the batmobile at a spotlight. As the light turns green, Robin passes Batman in his lime green pinto at a constant speed of 60km/h. If batman gives chase, accelerating at constant rate of 10km/h/s, determine
am completely off on my answers
a. how long it takes batman to attain same speed? answer :6.0
b. how far Batman travels in this time? ans: 50m
c. how long it takes for Batman to catch up to robin? ans : 12.0s
2. A squash ball makes contact with a squash racquet and changes from 15m/s to 25m/s east in 0.10s. determine the vector acceleration of the squash ball
Answers:a. The units as given are OK for this one. The speed changes by 10 km/h each second, and he wants to get to 60 km/h. So 60/10 = 6 seconds. b. You can use d = (1/2)at^2 for this, but to get an answer in meters you're going to have to convert the acceleration to m/sec^2. To do that, convert the km to meters (multiply by 1000) and the hr to seconds (divide by 3600). c. You can use d = (1/2)at^2 again, and again you need the value of a in m/sec^2. This time t is unknown. It is going to be more than 6 seconds and Batman is going to continue to accelerate (he won't catch Robin if he stops accelerating when he gets to 60, because Robin is far ahead of him, also doing 60). In the same time, Robin goes d = v*t, but you're going to have to convert his speed to m/sec also. Batman catches Robin when these distances are the same. (1/2)at^2 = v*t You can divide out one factor of t (1/2)at = v and you can rearrange that to solve for v. Actually come to think of it, you can use the original units of km/hr for v and km/hr/sec for a, since they are compatible in this equation. You've got km/hr on both sides so that would be OK. Number 2, just use the definition of acceleration. You have the change in velocity. You have the time. a = (change in velocity)/time
Answers:a. The units as given are OK for this one. The speed changes by 10 km/h each second, and he wants to get to 60 km/h. So 60/10 = 6 seconds. b. You can use d = (1/2)at^2 for this, but to get an answer in meters you're going to have to convert the acceleration to m/sec^2. To do that, convert the km to meters (multiply by 1000) and the hr to seconds (divide by 3600). c. You can use d = (1/2)at^2 again, and again you need the value of a in m/sec^2. This time t is unknown. It is going to be more than 6 seconds and Batman is going to continue to accelerate (he won't catch Robin if he stops accelerating when he gets to 60, because Robin is far ahead of him, also doing 60). In the same time, Robin goes d = v*t, but you're going to have to convert his speed to m/sec also. Batman catches Robin when these distances are the same. (1/2)at^2 = v*t You can divide out one factor of t (1/2)at = v and you can rearrange that to solve for v. Actually come to think of it, you can use the original units of km/hr for v and km/hr/sec for a, since they are compatible in this equation. You've got km/hr on both sides so that would be OK. Number 2, just use the definition of acceleration. You have the change in velocity. You have the time. a = (change in velocity)/time
Question:Our physics teacher drew a velocitytime graph showing a slanted ,straight line from the bottom left corner to the top right corner.
This obviously means that it is uniform acceleration, and nonuniform motion , because in acceleration , the body is covering unequal distances in equal time intervals.
But the teacher labeled it as a 'velocitytime for uniform motion when the object starts from rest'
When i contradicted , he refused.
Please help me.
Answers:uniform motion is not necisarily motion atthe same speed. uniform motion is where there is some regularity in the motion. an equal and exponential increase in velocity, is considered uniform motion.
Answers:uniform motion is not necisarily motion atthe same speed. uniform motion is where there is some regularity in the motion. an equal and exponential increase in velocity, is considered uniform motion.
Question:Hello~
So I was wondering how you would graph uniform accelerated motion.
I understand what the graph looks like when you graph acceleration versus time
and velocity versus time. But what is the other way you graph it?
And what equation do you use? Is it a = ( Vf  Vi ) / t and d = 1/2 ( Vf + Vi ) t ?
So basically Is there any other way to graph? (with mini explination)
I also found position versus time graph can anyone explain?
Thanks~
Answers:The key word is "motion". Motion is change in position with time. So in one dimension, you would graph X on one axis and time on the other. When you start calculus, you will realize what it all means. Velocity = Change in position with time. [m/s] Acceleration = Change in velocity with time.[(m/s)/s = m/s^2)
Answers:The key word is "motion". Motion is change in position with time. So in one dimension, you would graph X on one axis and time on the other. When you start calculus, you will realize what it all means. Velocity = Change in position with time. [m/s] Acceleration = Change in velocity with time.[(m/s)/s = m/s^2)
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Uniformly Accelerated Motion :
NTL Uniformly Accelerated Motion :SYSTEMTEKNIK INTL. TECHNOLOGIES CORP. NTL www.systemteknik.com.ph