definition of uniformly accelerated motion
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Answers:Motion implies momentum, which implies velocity. Linear implies a straight line. Accelerating implies changing velocity. And uniform implies constancy. So, when a body moves in a straight line and accelerates at a constant rate, the body is said to have an uniformly accelerated linear motion.
Answers:a. The units as given are OK for this one. The speed changes by 10 km/h each second, and he wants to get to 60 km/h. So 60/10 = 6 seconds. b. You can use d = (1/2)at^2 for this, but to get an answer in meters you're going to have to convert the acceleration to m/sec^2. To do that, convert the km to meters (multiply by 1000) and the hr to seconds (divide by 3600). c. You can use d = (1/2)at^2 again, and again you need the value of a in m/sec^2. This time t is unknown. It is going to be more than 6 seconds and Batman is going to continue to accelerate (he won't catch Robin if he stops accelerating when he gets to 60, because Robin is far ahead of him, also doing 60). In the same time, Robin goes d = v*t, but you're going to have to convert his speed to m/sec also. Batman catches Robin when these distances are the same. (1/2)at^2 = v*t You can divide out one factor of t (1/2)at = v and you can rearrange that to solve for v. Actually come to think of it, you can use the original units of km/hr for v and km/hr/sec for a, since they are compatible in this equation. You've got km/hr on both sides so that would be OK. Number 2, just use the definition of acceleration. You have the change in velocity. You have the time. a = (change in velocity)/time
Answers:uniform motion is not necisarily motion atthe same speed. uniform motion is where there is some regularity in the motion. an equal and exponential increase in velocity, is considered uniform motion.
Answers:The key word is "motion". Motion is change in position with time. So in one dimension, you would graph X on one axis and time on the other. When you start calculus, you will realize what it all means. Velocity = Change in position with time. [m/s] Acceleration = Change in velocity with time.[(m/s)/s = m/s^2)