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can a line segment have two midpoints explain
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From Wikipedia
The midpoint (also known as class mark in relation to histogram) is the middle point of a line segment. It is equidistant from both endpoints.
Formulas
The formula for determining the midpoint of a segment in the plane, with endpoints (x_{1}) and (x_{2}) is:
 \frac{x_1 + x_2}{2}
The formula for determining the midpoint of a segment in the plane, with endpoints (x_{1}, y_{1}) and (x_{2}, y_{2}) is:
 \left(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}\right)
The formula for determining the midpoint of a segment in the plane, with endpoints (x_{1}, y_{1}, z_{1}) and (x_{2}, y_{2}z_{2}) is:
 \left(\frac{x_1 + x_2}{2},\frac{y_1 + y_2}{2}, \frac{z_1 + z_2}{2}\right)
More generally, for an ndimensional space with axes x_1, x_2, x_3, \dots, x_n\,\!, the midpoint of an interval is given by:
 \left(\frac{x_{1_1} + x_{1_2}}{2}, \frac{x_{2_1} + x_{2_2}}{2}, \frac{x_{3_1} + x_{3_2}}{2}, \dots , \frac{x_{n_1} + x_{n_2}}{2} \right)
Construction
The midpoint of a line segment can be located by first constructing a lens using circular arcs, then connecting the cusps of the lens. The point where the cuspconnecting line intersects the segment is then the midpoint. It is more challenging to locate the midpoint using only a compass, but it is still possible.
In geometry, a line segment is a part of a line that is bounded by two end points, and contains every point on the line between its end points. Examples of line segments include the sides of a triangle or square. More generally, when the end points are both vertices of a polygon, the line segment is either an edge (of that polygon) if they are adjacent vertices, or otherwise a diagonal. When the end points both lie on a curve such as a circle, a line segment is called a chord (of that curve).
Definition
If V\,\! is a vector space over \mathbb{R} or \mathbb{C}, and L\,\! is a subset of V,\,\! then L\,\! is a line segment if L\,\! can be parameterized as
 L = \{ \mathbf{u}+t\mathbf{v} \mid t\in[0,1]\}
for some vectors \mathbf{u}, \mathbf{v} \in V\,\!, in which case the vectors \mathbf{u} and \mathbf{u+v} are called the end points of L.\,\!
Sometimes one needs to distinguish between "open" and "closed" line segments. Then one defines a closed line segment as above, and an open line segment as a subset L\,\! that can be parametrized as
 L = \{ \mathbf{u}+t\mathbf{v} \mid t\in(0,1)\}
for some vectors \mathbf{u}, \mathbf{v} \in V\,\!.
An alternative, equivalent, definition is as follows: A (closed) line segment is a convex hull of two points.
Properties
 A line segment is a connected, nonemptyset.
 If V is a topological vector space, then a closed line segment is a closed set in V. However, an open line segment is an open set in V if and only if V is onedimensional.
 More generally than above, the concept of a line segment can be defined in an ordered geometry.
In proofs
In geometry, it is sometimes defined that a point B is between two other points A and C, if the distance AB added to the distance BC is equal to the distance AC.
In an axiomatic treatment of Geometry, the notion of betweenness is either assumed to satisfy a certain number of axioms, or else defined in terms of an isometry of a line (used as a coordinate system).
Segments play an important role in other theories. For example, a set is convex if the segment that joins any two points of the set is contained in the set. This is important because it transforms some of the analysis of convex sets to the analysis of a line segment.
From Yahoo Answers
Answers:You take the length of the segment and divide it by two. If it is on a coordinate plane, then you average the x and y values, (add both up and divide by two), and take those averages, and they are the coordinates of the midpoint.
Answers:a.) Put A on the xaxis, so it must have coordinates of (x, 0). Put B on the yaxis, so it must have coordinates (0, y). Midpoint formula, where x(m) is the xcoordinate of the midpoint, and y(m) is the ycoordinate of the midpoint: (x(m), y(m)) = [((x(a) + x(b))/2, ((y(a) + y(b))/2] Plug in what you know: (2, 1) = [(x + 0)/2, (0 + y)/2] So, one coordinate at a time, xcoordinate first: 2 = (x + 0)/2 4 = x + 0 4 = x ycoordinate: 1 = (0 + y)/2 2 = 0 + y 2 = y The points are... A: (4, 0) B: (0, 2) b.) This one doesn't use formulas...it is a "what if" question. C is in Quadrant I. If A is on the xaxis, B could be in Quadrant I or Quadrant II. If A is on the yaxis, B could be in Quadrant I or Quadrant IV. Hope that helps!
Answers:False! A line, by definition, continues off to infinity in both directions. Therefore, it doesn't have a midpoint. If you think of the number line, you might consider 0 to be its midpoint. However, that's not quite accurate. You could just as easily consider 347 to be the midpoint, since for any integer n, you can find (347 + n) and (347  n) on the number line. By this reasoning, 347 is just as good of a "midpoint candidate" as 0 is. A line segment will always have a midpoint, but a line segment isn't the same thing as a line. Hope that helps!
Answers:You have the coordinates (x1,y1) of the midpoint, the slope m and the length L. Use the slope formula: m = (y2y1)/(x2x1) and the distance formula: d = L/2 = {y2y1)^2 + (x2x1)^2} To create two equations in x2 and y2. Now you have two variables and two equations so you can get the values (x2,y2) for the upper end of the line and for the lower end.
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