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Question:Each binary digit is termed a bit. A series of 8 bits is grouped together into a word, which is called a byte. A byte can represent 28 = 256 different combinations, which is sufficient to record a typical 8letter word in a sentence. A typical 400 page book has about 2 x 105 words. Estimate the number of books that can be stored on a 1.35 gigabyte computer.
Answers:28 does not = 256. 2^8 does. But storing 8 letters in one byte is not resonable unless you are using a compression scheme. Typically, uncompressed text is one byte per letter or character, in ASCII. A two letter word, not counting capitals, could be one of 26 times 26 possible combinations, which is much more than 16 times 16 = 256. 2 x 105 = 210, which is only half a word per page. 2^105 is more likely. Also, 1 gigabyte can be 1 times 10^9 = (1000) ^3 bytes if you talk to a hard drive manufacturer, or it can be 2^30 = ( 1024 ) ^ 3 as Windows displays it. regardless, divide 1.35 x 10^9 bytes by 2^105 words per book, to get the number of "byte books per word." Then divide by the number of "bytes per word" to get the number of books.
Answers:28 does not = 256. 2^8 does. But storing 8 letters in one byte is not resonable unless you are using a compression scheme. Typically, uncompressed text is one byte per letter or character, in ASCII. A two letter word, not counting capitals, could be one of 26 times 26 possible combinations, which is much more than 16 times 16 = 256. 2 x 105 = 210, which is only half a word per page. 2^105 is more likely. Also, 1 gigabyte can be 1 times 10^9 = (1000) ^3 bytes if you talk to a hard drive manufacturer, or it can be 2^30 = ( 1024 ) ^ 3 as Windows displays it. regardless, divide 1.35 x 10^9 bytes by 2^105 words per book, to get the number of "byte books per word." Then divide by the number of "bytes per word" to get the number of books.
Question:Solve the following 2 problems:
1. Solve for x:
(3)(sqrt2x) 10 = 0
<< I got x =8 >>
2. Solve for the negative value of x:
(x  3) ( x  2) = (x + 5) (2x  3) + 21
<< Is it 1/500 (0.002) ?? >>
Find the product of your answers. Raise this product to the power of the absolute value of the sum of your answers.
<< I don't understand this part at all!! >>
I need that final answer mostly! If you can explain how you got it great, but if not just the answer is fine so that I can use it to get to the last Box #9!
Here is the website to the actual problem, it is easier for you to understand there:
http://mathbits.com/Caching/A16807.html
I've been working on this for many hours so any help is much appreciated!!!!!!!
Answers:Solve the following 2 problems: 1. Solve for x: (3)(sqrt2x) 10 = 0 << I got x =8 >> This is correct. 2. Solve for the negative value of x: (x  3) ( x  2) = (x + 5) (2x  3) + 21 << Is it 1/500 (0.002) ?? >> This is however wrong. The answer should be x = 0 or 12 when you solve the quadratic equation. Since the negative value is required, x=12. For this part... Find the product of your answers. Raise this product to the power of the absolute value of the sum of your answers. To find the product, take 8 mutiply by 12 and you get 96. The absolute value of the sum of your answers is calculated you take 12 + 8 which gives 4 and taking absolute will give 4. So taking 96 to the power of 4 gives you 84934656. I tried it and it works! =) I hope it helped. Good luck!
Answers:Solve the following 2 problems: 1. Solve for x: (3)(sqrt2x) 10 = 0 << I got x =8 >> This is correct. 2. Solve for the negative value of x: (x  3) ( x  2) = (x + 5) (2x  3) + 21 << Is it 1/500 (0.002) ?? >> This is however wrong. The answer should be x = 0 or 12 when you solve the quadratic equation. Since the negative value is required, x=12. For this part... Find the product of your answers. Raise this product to the power of the absolute value of the sum of your answers. To find the product, take 8 mutiply by 12 and you get 96. The absolute value of the sum of your answers is calculated you take 12 + 8 which gives 4 and taking absolute will give 4. So taking 96 to the power of 4 gives you 84934656. I tried it and it works! =) I hope it helped. Good luck!
Question:
Answers:Check the back of the book for the odd problems. OR GOOGLE !!!! LOL
Answers:Check the back of the book for the odd problems. OR GOOGLE !!!! LOL
Question:lesson 10.5
Answers:Can you write down the questions? Many of us are not in your math class so we don't have the book... sorry...
Answers:Can you write down the questions? Many of us are not in your math class so we don't have the book... sorry...
From Youtube
Bits of Me Are Falling Apart, William Leith :www.bloomsbury.com William Leith on latest book Bits of Me Are Falling Apart published by Bloomsbury, follow up to The Hungry Years. One morning in August 2007, William Leith wakes up and realises that something is wrong. He is not in a bed, but on an old mattress on the floor. He is not in a house. He is in his office. He is alone. He no longer lives with his little boy and the mother of his little boy. Mentally, he is at the end of his tether. Physically, he is fraying at the edges. Bits of him are falling apart. But then again, so is everything else  the economy, the environment, the very fabric of society. With his trademark darkly humorous mix of personal story and social commentary, Leith attempts to answer the question: is everything really falling apart? Or is it just him? He examines the ageing process in humans, and in everything else as well, from the universe to the banking system. And he comes to realise that, even if he can't solve the problems of the world, at least he has a thorough understanding of failure.