benzoic acid sodium hydroxide
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Answers:Both Napthalene and Bezoic acid are soluble in diethyl ether. When sodium hydroxide dissoved in water is shaken into the either, the benzoic acid forms sodium benzoate which is highly ionized and polar, and more soluble in water than the ether. Thefore the bezoic acid moves out of the either. Heat and water are also made in the process. The sodium hydroxide in water also minimized the solubility of either in water, therefore minimizing the water content dissolved into the either. The naphthalene is kept in the either phase, but sodium sulfate is needed to remove some of the water that had dissolved into the either, so the ether phase is dry enough to evaporate without leaving a water residue. HCl restores the benzoic acid and neutralized the excess sodium hydroxide, making sodium chloride which is water soluble, and pass through the filter with the water while the water insoluble benzoic acid is filtered out. The salt in the water also helps salt out low soluble and insoluble substances from the water.
Answers:Add water and NaHCO3 to the mixture. Sodium benzoate will form. Add diethyl ether to the mixture and shake. The ether will dissolve the phenol and the neutral compond. Sodium benzoate will remain the the water layer. Add HCl to the water layer to precipitate benzoic acid. Shake the ether solution with sodium hydroxide solution. This will dissolve the phenol into the water layer as soduium phenolate. Add HCl to the water layer to separate the phenol. The ether layer next contains the neutral compound. Evaporate the ether to isolate the neutral compound.
Answers:C8H6O4 (aq) + NaOH(aq) = C8H5O4^2-(aq) + Na+(aq) + H2O(l) moles KHP = moles NaOH 0.1235 g/ 204.22 g = 0.0389 L (M) M = 0.016 M :)
Answers:moles SO2 = 1.03 atm x 0.195 / 0.0821 x 292 K = 0.00838 = moles H2SO3 moles NaOH required = 2 x 0.00838= 0.0168 M = 0.0168/ 0.0100 L =1.68