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benzoic acid sodium hydroxide

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Question:Can someone tell me the mechanisms involved in this process? 1g of a 1:1 mix of naphthalene and benzoic acid were dissolved in diethyl ether, then extracted using first NaOH, then water. the separated liquids: naphthalene in ether - mixed with anhydrous sodium sulfate and then filtered and dried; ended up with pure napthalene NaOH extract containing benzoic acid - HCl added, chilled, then filtered to get pure benzoica cid crystals. I've figured out the acid extraction half...still working on the Naphthalene though :) oops it looks like I got an answer for the acid part just as I posted that last uupdate >_< thanks!!! Still working on the naphthalene + sodium sulfate part

Answers:Both Napthalene and Bezoic acid are soluble in diethyl ether. When sodium hydroxide dissoved in water is shaken into the either, the benzoic acid forms sodium benzoate which is highly ionized and polar, and more soluble in water than the ether. Thefore the bezoic acid moves out of the either. Heat and water are also made in the process. The sodium hydroxide in water also minimized the solubility of either in water, therefore minimizing the water content dissolved into the either. The naphthalene is kept in the either phase, but sodium sulfate is needed to remove some of the water that had dissolved into the either, so the ether phase is dry enough to evaporate without leaving a water residue. HCl restores the benzoic acid and neutralized the excess sodium hydroxide, making sodium chloride which is water soluble, and pass through the filter with the water while the water insoluble benzoic acid is filtered out. The salt in the water also helps salt out low soluble and insoluble substances from the water.

Question:We are given a mixture of benzoic acid, phenol, and an unknown neutral compound. Using the information that phenol is soluble in aqueous NaOH but not in NaHCO3, and benzoic acid is soluble in both, how would you seperate this mixture? Any help is appreciated

Answers:Add water and NaHCO3 to the mixture. Sodium benzoate will form. Add diethyl ether to the mixture and shake. The ether will dissolve the phenol and the neutral compond. Sodium benzoate will remain the the water layer. Add HCl to the water layer to precipitate benzoic acid. Shake the ether solution with sodium hydroxide solution. This will dissolve the phenol into the water layer as soduium phenolate. Add HCl to the water layer to separate the phenol. The ether layer next contains the neutral compound. Evaporate the ether to isolate the neutral compound.

Question:Sodium hydroxide solution is usually standardized by titrating a pure sample of potassium hydrogen phthalate (KHP), an acid with one acidic hydrogen and a molar mass of 204.22 g. It takes 38.90 mL of a sodium hydroxide solution to titrate a 0.1235 g sample of KHP. What is the molarity of the sodium hydroxide?

Answers:C8H6O4 (aq) + NaOH(aq) = C8H5O4^2-(aq) + Na+(aq) + H2O(l) moles KHP = moles NaOH 0.1235 g/ 204.22 g = 0.0389 L (M) M = 0.016 M :)

Question:Aqueous sulfurous acid (H2SO3) was made by dissolving 0.195 L sulfur dioxide gas at 19 C and 780. mmHg in water to yield 500.0 mL of solution. The acid solution required 10.0 mL of sodium hydroxide solution to reach the titration end point. What was the molarity of the sodium hydroxide solution?

Answers:moles SO2 = 1.03 atm x 0.195 / 0.0821 x 292 K = 0.00838 = moles H2SO3 moles NaOH required = 2 x 0.00838= 0.0168 M = 0.0168/ 0.0100 L =1.68

From Youtube

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