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# balanced equation for zinc and hydrochloric acid

Question:hey guys I need to write a balanced chemical equation for hydrochloric acid and zinc. can ya help me out? thanks!

Answers:Zn + 2 HCl -----> ZnCl2 + H2

Question:Zinc is solid and hydrochlorics acid is liquid. Equation and states (l, g, s, aq) of products? also what type of reaction is it?

Answers:Zn (s) + 2HCl (aq) ---> ZnCl2(aq) + H2(g) There are several ways of describing the reaction type. You can say that it is exothermic, cation replacement or even single displacement reaction. It all depends on the context.

Question:1) Zinc metal reacts with hydrochloric acid to produce zinc chloride and hydrogen gas. write a balanced chemical equation. 2) for the reaction give in #1, calculate how many grams of hydrogen would be produced if 15g of Zinc was reacted with a sufficient amount of hydrochloric acid? 3) Indicate which is the reducing agent and oxidizing agent in equation #1?

Answers:1) Zn (s) + 2HCl (aq) > ZnCl2 (aq) + H2 (g) 2) number of moles of zinc = mass/Ar = 15/65 = 3/13 molar ratio of Zn:H2 = 1:1, therefore number of moles of hydrogen = 3/13 mass of hydrogen = moles x Mr = 3/13 x (1x2) = 6/13g or 0.462g 3) zinc, Zn is the reducing agent because its oxidation state increases from 0 to 2 and hydrochloric acid, HCl is the oxidizing agent because it loses hydrogen ions, H+

Question:When a piece of zinc metal is placed in aqueous hydrochloric acid, zinc chloride is produced and hydrogen gas is evolved. Write a balanced chemical equation for this reaction. Decide which reactant is in excess for each of the following combinations of reactants. 79.3g of HCL and 46.3G of ZN will be and 5.92 mol of HCL and 95.5 of ZN and 5.42 10^23 molecules of zn and 67.1 of hcl and 3.78 mole of zn and 119 of hcl

Answers:Zn + 2 HCl = H2 + ZnCl2 79.3 g of HCl x 1 mol /36 g = 2.2 mol HCl 46.3 g Zn x 1 mol / 65 g = 0.71 mol Zn Zn is limiting (gives 0.71 mol of H2), whereas 2.2 mol of HCl would give 1.1 mol of H2. HCl is in excess. You figure out the rest.