#### • Class 11 Physics Demo

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# balanced equation for the combustion

Question:Write the balanced equation for the combustion of the alkane parrafin (candle wax).

Answers:Paraffin refers to a range of alkanes, not a specific compound. The formula is CnH2n+2, where n has a value in the range of 20 to 40 (approximately). If n equals 30, then- 2 C30H62 + 91 O2 --> 60 CO2 + 62 H2O

Question:Write the balanced equation for the combustion of alkane paraffin (candle wax). Candle (paraffin wax) = C25 H52 (25 Carbons and 52 Hydrogens)

Answers:C25H52 + 38 O2 --> 25 CO2 + 26 H2O

Question:The question is as follows: Write a balanced equation for the complete combustion of each of the following alkanes: A) Propane B) Heptane C) Nonane D) Decane

Answers:A) C3H8 + 5O2 ===> 3CO2 + 4H2O B) C7H16 + 11O2 ===> 7CO2 + 8H2O C) C9H20 + 14O2 ===> 9CO2 + 10H2O D) 2C10H22 + 31O2 ===> 20CO2 + 22H2O

Question:Write a balanced chemical equation for the combustion of hydrogen gas. If you start with 8 g of hydrogen and you produce 55 g of water what is the % yield?

Answers:Molar mass H2 = 2g/mol Molar mass O2 = 32g/mol Molar mass H2O = 18g/mol 2H2 + O2 2H2O That is the balanced equation 2mol H2 react with 1 mol O2 to produce 2mol H2O 4g H2 reacts with 32g O2 to produce 36g H2O Your question: 8g H2 will react with 64g O2 to produce 72g H2O But you produced only 55g H2O % yield = 55/72*100 = 76.4% yield