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answers to math xl problems
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Question:2(k11)
MY ANSWER: 2k22
(42b)
MY ANSWER: 42b
5(b5)
MY ANSWER: 5b25
Are those correct? If not, explinations please? Thanksss! :)
Answers:First: 2(k11)= 2k+22> 2(k) is 2 but 2(11)=22 Second: (42b)= 4+2b> a negative multipled by a negative is a positive. Third: 5(b5)= 5b+25> Again, when you multiply the 5 by the 5 the answer is +25. I hope this helps. Feel free to contact me with you need further clarification.
Answers:First: 2(k11)= 2k+22> 2(k) is 2 but 2(11)=22 Second: (42b)= 4+2b> a negative multipled by a negative is a positive. Third: 5(b5)= 5b+25> Again, when you multiply the 5 by the 5 the answer is +25. I hope this helps. Feel free to contact me with you need further clarification.
Question:1.) Pizza pies can be ordered in 3 sizes(small, medium, large), 2 crust choices(thick,thin), 4 choices of meat toppings(sausage only, pepperoni only, both, or neither) and 2 cheese toppings(regular or double). How many ways can a pizza pie be ordered?
2.) A group of children are standing in a circular arrangement. They are evenly spaced and numbered in order. The 7th child is directly opposite the 17th child. How many children are in the arrangement?
3.) The maximum number of regions into which two chords can divide a circle is 4. What if there are 3 chords? 20 chords?

hello mathlovers out there! PLease help me answer these problems... we'll have our periodicals this coming Monday and i still find it hard to know when to use permutation or combination! so for those kind hearted mathlovers, please help me through step by step solution! and some tips :)
thankkkkkkkksssssssssss
Answers:1) n = 3! x 2! x 4! x 2! n = 864 2) 9 children is in between 7 and 17 (on one side). So the other 9 is on the other side. Total = 9 + 9 + #7 + #17 Total = 20 3) 1 chord = 2 2 chords = 4 3 chords = 7 4 chords = 11 5 chords = 16
Answers:1) n = 3! x 2! x 4! x 2! n = 864 2) 9 children is in between 7 and 17 (on one side). So the other 9 is on the other side. Total = 9 + 9 + #7 + #17 Total = 20 3) 1 chord = 2 2 chords = 4 3 chords = 7 4 chords = 11 5 chords = 16
Question:A new school is being opened. The school has exactly 1000 lockers and 1000 students. On the first day of school, the students meet outside the building and agree on the following plan: The first student will enter the school and open all of the lockers. The second student will enter and close every locker with an even number. The third student will then "reverse" every third locker; that is, if the locker is closed, he will open it; if its open,he will close it. The fourth student will then "reverse" every fourth locker; and so on until all 1000 students in turn have entered the building and "reversed" the proper lockers. Which lockers will finally remain open?
I know what the answer is, it's 31, but can someone explain to me why this is?
Answers:There are two things you need to know: First, each locker will be touched by the students who are multipliers of that locker. For example, locker number 18 will be touched by students number 1, 2, 3, 6, 9, and 18. So in this case 6 students touched this locker, and so when it was all set and done, this locker remained close. Second, the only numbers that have odd number of multipliers are the perfect squares. For example the multiplier for number 25 are 1, 5, and 25. So you can see that the locker number 25 will remain open. So the lockers that will remain open are 1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144, 169, 196, 225, 256, 289, 324, 361, 400, 441, 484, 529, 576, 625, 676, 729, 784, 841, 900, 961 I hope this helped Kia
Answers:There are two things you need to know: First, each locker will be touched by the students who are multipliers of that locker. For example, locker number 18 will be touched by students number 1, 2, 3, 6, 9, and 18. So in this case 6 students touched this locker, and so when it was all set and done, this locker remained close. Second, the only numbers that have odd number of multipliers are the perfect squares. For example the multiplier for number 25 are 1, 5, and 25. So you can see that the locker number 25 will remain open. So the lockers that will remain open are 1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144, 169, 196, 225, 256, 289, 324, 361, 400, 441, 484, 529, 576, 625, 676, 729, 784, 841, 900, 961 I hope this helped Kia
Question:1.) the lowest common multiple of the two numbers is 48, if you divide the sum of the two numbers by their gcf the the result is 5, the average of the two numbers is 20. 2.) the numerator and denominator of this fraction have the same digits in reverse order, the GCF of the numerator and denominator is 3, When the fraction is simplified the sum of the numerator and denominator is a prime number, the difference of the numerator and denominator of the simplified fraction is 3.
Answers:1. 16 and 24 2. 12/21 (or 21/12)
Answers:1. 16 and 24 2. 12/21 (or 21/12)
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