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Analytical Math Problems
Analytical Geometry :Analytical Geometry is a unit of mathematics with study of coordinate system,conic section,circle,equation of line.
Analytical Math Problem
1. What is the center of the circle x^{2 }+ y^{2 } 4x  y + 5 = 0
a) (2,1) b) (3,2) c) (2,$\frac{1}{2}$) d) (3,$\frac{1}{3}$)
2. Express $\frac{21}{27}$ in standard form
a) $\frac{7}{9}$ b) $\frac{3}{5}$ c) $\frac{7}{5}$ d) $\frac{7}{4}$
a) odd b) even c) an irrational number d) none of the above
3. IF x^{y}, is an even integer then value of x and y is
a) odd b) even c) an irrational number d) none of the above
4. Calculate the gradient of the line AB (1,5) and (4,6)
a) $\frac{12}{3}$ b) $\frac{11}{3}$ c) $\frac{21}{7}$ d) $\frac{11}{3}$
a) Parabola b) Ellipse c) Hyperbola d) None
a) √9 b) √3 c) 3√2 d) 0
a) y = 2x + 3 b) y = 2x + 1 c) y = 2x + 5 d) y = 5x + 3
5. If Eccentricity is equal to 1,then the conic is called as
a) Parabola b) Ellipse c) Hyperbola d) None
6. Find the distance between A (3; 4) and B (6; 7)
a) √9 b) √3 c) 3√2 d) 0
7. Find the equation of the line with gradient = –2 passing through A (3,7)
a) y = 2x + 3 b) y = 2x + 1 c) y = 2x + 5 d) y = 5x + 3
8. the point (–6; –2) and perpendicular to 3x + 2y = 6
a) $\frac{2}{3}$ b) $\frac{3}{2}$ c) $\frac{2}{5}$ d) none
9. In the given figure, C is the midpoint of AB. Calculate the value of x and y.
a) (2,5) b) (3,2) c) (5,3) d) (2,7)
Analytic Geometry Formula:
Mid point formula: $\left ( \frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2} \right )$
9. In the given figure, C is the midpoint of AB. Calculate the value of x and y.
10. Find the midpoint of the line joining A(6; 4) and B(2;5)
a) (2,5) b) (3,2) c) (5,3) d) (2,7)
11. What is the equation of Parabola
12. What is the standard form of equation of ellipse
Analytic Geometry Formula:
Mid point formula: $\left ( \frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2} \right )$
The distance formula is used to find the distance between two points A (x_{1} ; y_{1}) and B (x_{2}; y_{2})
AB = $\sqrt{\left ( X_{2}X_{1} \right )^{2}+\left ( Y_{2}Y_{1} \right )^{2}}$
The gradient of the line = $\frac{Y_{2}Y_{1}}{X_{2}X_{1}}$
AB = $\sqrt{\left ( X_{2}X_{1} \right )^{2}+\left ( Y_{2}Y_{1} \right )^{2}}$
The gradient of the line = $\frac{Y_{2}Y_{1}}{X_{2}X_{1}}$
The equation of a straight line is given by y = mx + c
The equation of the perpendicular bisector = y – y_{1} = m(x – x_{1})
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From Yahoo Answers
Question:This was my girlfriend's extra credit problem last semester and no one in her class was able to solve it without using a calculator. Not even my girlfriend's aunt, who is a high school math teacher, was able to solve it.
(7x  2)^(1/3) + (7x + 5)^(1/3) = 3 I attempted both approaches in earnest and neither of them yielded anything I deemed useful. Thanks for the suggestions though.
Answers:Well, one answer is obviously 3/7, that can be found out just by looking upon the problem. Now, function x^(1/3) is monotone increasing (because f(x) is monotone increasing if f'(x)>0, and (x^(1/3))'=(1/3)x^(2/3)>0), so (7x  2)^(1/3), (7x + 5)^(1/3) and (7x  2)^(1/3) + (7x + 5)^(1/3) are monotone increasing too, so the graphic of function f(x)=(7x  2)^(1/3) + (7x + 5)^(1/3) can have only one point of crossing with any horizontal line, such as f(x)=3, and therefore it has only one salvation which is 3/7.
Answers:Well, one answer is obviously 3/7, that can be found out just by looking upon the problem. Now, function x^(1/3) is monotone increasing (because f(x) is monotone increasing if f'(x)>0, and (x^(1/3))'=(1/3)x^(2/3)>0), so (7x  2)^(1/3), (7x + 5)^(1/3) and (7x  2)^(1/3) + (7x + 5)^(1/3) are monotone increasing too, so the graphic of function f(x)=(7x  2)^(1/3) + (7x + 5)^(1/3) can have only one point of crossing with any horizontal line, such as f(x)=3, and therefore it has only one salvation which is 3/7.
Question:What would be the absorbance of the gaseous ozone if its total pressure is doubled?
This is a question from my professor. How to solve this problem? Thanks.=)
Answers:The BeerLambert Law states that absorbance is linearly proportional to the concentration of the ozone in your sample. So if the pressure is doubles, then so does the concentration. Absorbance doubles.
Answers:The BeerLambert Law states that absorbance is linearly proportional to the concentration of the ozone in your sample. So if the pressure is doubles, then so does the concentration. Absorbance doubles.
Question:I'm going back to school this fall and I plan on taking Calculus with Analytic Geometry I, II, III, instead of the other math classes like college algebra and calculus.
I'm pursuing an engineering degree and that math class is required... (math is my worse subject.... 4 years ago)
I dont remember much of the stuff at all really, but I'm thinking they teach you everything along the way anyway.. I dont remember everything from algebra or geometry either...
But I plan on studying my butt off and working hard for a good grade so... Am I wasting my time for the inevitable F or no its a piece of cake and can be done no problem?
Thanks all for your help and opinion~!
Answers:Your school should offer a mathematics placement test to determine if you should be in Calculus, Pre Calculus or Algebra. A calculus class inevitably reviews many concepts of Algebra, geometry, graphing and trigonometry as nearly all students forget important concepts. However, if you forget many of the important concepts and need them retaught, it is unwise for you to plunge into Calculus, reviews are 8 to 20 times quicker than initial coverage in an Algebra or Pre Calculus class and that would result in an inevitable F. That is a particularly bad idea if you want an engineering degree because you also have to master physics, chemistry, and possibly statistics, and the applied engineering classes. You may want to look at a sample practice test on a site such as http://www.oaklandcc.edu/MathTest/ You will want to determine if you understand topics such as (1) Evaluating Functions (2) Finding the domain and range of a function y=f(x) for example What is the domain of y = 5/(x  5x + 6) Here's the answer. Domain is all real values of x except x= 2 and x=3 which is written, in interval notation as ( ,2)U(2,3)U(3, ) . That is because the denominator is not allowed to equal zero and x  5x + 6 factors to (x2)(x3) . If that was easy for you to read and understand, you may be ready to go to Calculus. If the explanation above raced over your head, you better keep your rear end out of Calculus and take Algebra or Pre calculus (3) Another incredibly important topic for Calculus is the algebra and graphing concepts of lines, slopes of lines, and equations of lines. Do you remember the a. Slope formula m = (y2  y1)/(x2  x1) for the slope of a line through (x1,y1) and (x2,y2) b. Slope intercept form for the equation of a line y = mx + b c. distance formula d = square root of [(x2x1) + (y2 y1) ] d. midpoint formula The midpoint of a line joining (x1, y1) and (x2, y2) is { (x1+x2)/2 , (y1 + y2)/2 } The slope concept is incredibly important because it similar to a generalized concept you will learn in Calculus that we call a "derivative" . If you don't know lines and slopes, and you don't learn them during Calculus class's quick review of the topic your goose will get cooked. You could, self study algebra and calculus by borrowing texts, reading the text and practicing odd problems and checking your answers. I've self studied plenty of times, however most students find that a difficult approach. If you need to be in beginning Algebra and you start there, you can study your butt off and get grades ranging from 92 to 100+ (if extra credit is offered) . If you can start where you belong and get consistent A's you will be more confident and more competent when you arrive at Calculus. If you rush through the class and have an F's competence and receive a D or C through a professor's mercy, you will not be prepared to excel or even pass an engineering program. Please get your school to give you a placement test if it is available. If you can answer most of the questions or all of them on a test like the included placement, you are ready to take Calculus. Calc is never a piece of cake . Best of Luck
Answers:Your school should offer a mathematics placement test to determine if you should be in Calculus, Pre Calculus or Algebra. A calculus class inevitably reviews many concepts of Algebra, geometry, graphing and trigonometry as nearly all students forget important concepts. However, if you forget many of the important concepts and need them retaught, it is unwise for you to plunge into Calculus, reviews are 8 to 20 times quicker than initial coverage in an Algebra or Pre Calculus class and that would result in an inevitable F. That is a particularly bad idea if you want an engineering degree because you also have to master physics, chemistry, and possibly statistics, and the applied engineering classes. You may want to look at a sample practice test on a site such as http://www.oaklandcc.edu/MathTest/ You will want to determine if you understand topics such as (1) Evaluating Functions (2) Finding the domain and range of a function y=f(x) for example What is the domain of y = 5/(x  5x + 6) Here's the answer. Domain is all real values of x except x= 2 and x=3 which is written, in interval notation as ( ,2)U(2,3)U(3, ) . That is because the denominator is not allowed to equal zero and x  5x + 6 factors to (x2)(x3) . If that was easy for you to read and understand, you may be ready to go to Calculus. If the explanation above raced over your head, you better keep your rear end out of Calculus and take Algebra or Pre calculus (3) Another incredibly important topic for Calculus is the algebra and graphing concepts of lines, slopes of lines, and equations of lines. Do you remember the a. Slope formula m = (y2  y1)/(x2  x1) for the slope of a line through (x1,y1) and (x2,y2) b. Slope intercept form for the equation of a line y = mx + b c. distance formula d = square root of [(x2x1) + (y2 y1) ] d. midpoint formula The midpoint of a line joining (x1, y1) and (x2, y2) is { (x1+x2)/2 , (y1 + y2)/2 } The slope concept is incredibly important because it similar to a generalized concept you will learn in Calculus that we call a "derivative" . If you don't know lines and slopes, and you don't learn them during Calculus class's quick review of the topic your goose will get cooked. You could, self study algebra and calculus by borrowing texts, reading the text and practicing odd problems and checking your answers. I've self studied plenty of times, however most students find that a difficult approach. If you need to be in beginning Algebra and you start there, you can study your butt off and get grades ranging from 92 to 100+ (if extra credit is offered) . If you can start where you belong and get consistent A's you will be more confident and more competent when you arrive at Calculus. If you rush through the class and have an F's competence and receive a D or C through a professor's mercy, you will not be prepared to excel or even pass an engineering program. Please get your school to give you a placement test if it is available. If you can answer most of the questions or all of them on a test like the included placement, you are ready to take Calculus. Calc is never a piece of cake . Best of Luck
Question:Solve for this equation: (find the value of "v" for the given parameters)
k(v^c)/(1v) = 1.
Parameters include 0 0.
(So the fraction will always be +ve, and = 1).
'v' is the variable here, while 'c' and 'k' are given constants.
For instance, if c = ln 4/ln 3, and if k = 91^(c1), then, m = 27/91 exactly.

Good luck! oops.. I wrote 'm' by mistake; I meant v = 27/91! Nick  I know there are special cases  that's there in every math problem. And in the example I gave, 'c' was definitely not an integer ln 4/ln 3.. so I'm really not looking for an integer solution; I did not make that specialization  I'm looking for an analytical solution. I'm not sure if I should say thanks for trying :/ but the question, as you can see, is not asking for a 'specialized' case.. I did mention that if there was a specialized case (like the one I gave as an example), then of course it's easy to solve. You're kinda telling me back what I'm trying to say anyway =.= The thing is, there is a limit to this equation .. to the 'solution', I mean. And it is dependent on k, c. I would like to see if there's a way to find the limit, or something close to it for an approximation. It's basically solving m(x^d) + x = 1, where m, d are constants. I guess though  out of courtesy  thanks for your answer.
Answers:If k=0, there's no solution. Otherwise, multiply through by 1v to obtain k v^c + v  1 = 0. If c is an integer between 3 and +4 inclusive, then we can solve the polynomial by radicals. Otherwise, there's no reason to expect to be able to solve the equation for general c and k. Of course there will be particular lucky cases, like the one you cooked up: let w be whatever you want (strictly between 0 and 1) and take k = (1w)/w^c; then v=w is a solution. In response to your reply, the answer is negative: unless c is one of those integers, there is no explicit, closed form solution. There is a (fairly) smooth solution, and, as you say, you can approximate it iteratively point by point, but it's just the inverse of the function given by k v^c + v  1 = 0.
Answers:If k=0, there's no solution. Otherwise, multiply through by 1v to obtain k v^c + v  1 = 0. If c is an integer between 3 and +4 inclusive, then we can solve the polynomial by radicals. Otherwise, there's no reason to expect to be able to solve the equation for general c and k. Of course there will be particular lucky cases, like the one you cooked up: let w be whatever you want (strictly between 0 and 1) and take k = (1w)/w^c; then v=w is a solution. In response to your reply, the answer is negative: unless c is one of those integers, there is no explicit, closed form solution. There is a (fairly) smooth solution, and, as you say, you can approximate it iteratively point by point, but it's just the inverse of the function given by k v^c + v  1 = 0.
From Youtube
Analytic Epistemology :This clip discusses some of the schools of thought in contemporary analytic epistemology. First, the clip mentions Bertrand Russells dislike for the standard notion of what constitutes "knowledge" in philosophy, believing it to be to much too vague. Then there is a brief summary of GE Moore's "Proof of an External World" and his views on foundationalism. The clip then mentions Ludwig Wittgenstein's idea that "meaning is use" within social contexts, and that philosophical obstacles are really just miscommunication within "language games." Simply put, Wittgenstein thought that there were no such things as genuine philosophical problems, and that philosophy was merely a byproduct of linguistic misunderstandings. The clip then discusses the differences between foundationalism and coherentism and WVO Quine's notion of the seamless "web of belief." Quine was a strong proponent of the natural sciences, and thought that findings in the natural sciences could shed significant light onto ageold philosophical questions concerning the nature of the mind and knowledge. The clip then summarizes "The Gettier Problem" which challenged the Platonic definition of knowledge as "justified true belief," and then ends with definitions of internalism/externalism, and Alvin Goldman's causal theory of knowledge.
Maths 911 Grade 11 Analytical Geometry :Maths 911 Live Show Grade 11 Analytical Geometry:Gradient of a Straight Line Presenter:John Luis Executive Producer:Dylan Green