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7th Grade Math Formula Chart
7th Grade Math Formula ChartThe Formula chart gives easy understanding and explanation of concept for referral of students.7th grade math formula chart is created based on the revised edition of the latest syllabus and curriculum guidelines.
Formula chart:
A list of formula chart are given below for student reference.
Speed and Time:
Speed = $\frac{distance\ travelled}{Time\ taken}$
Number of revolution = $\frac{Distance\ travelled}{Circumference\ of\ the\ wheel}$
Percentage and its Application:
Loss = C.P = S.P
The profit or loss percentage can be calculated as $\frac{profit/loss}{cost\ price}$*100
S.P = $\frac{100+profit}{100}$*C.P
S.P = $\frac{100loss}{100}$*C.P
C.P = $\frac{100}{100+profit}$*S.P
C.P = $\frac{100}{100profit}$*S.P
Interest:
When rate of discount is given Discount = $\frac{MP*Rate\ of\ discount}{100}$
Simple Interest = $\frac{PTR}{100}$
where P = Principal , T = Time in years R = Rate of interest per annum
Area:
Speed and Time:
Speed = $\frac{distance\ travelled}{Time\ taken}$
Number of revolution = $\frac{Distance\ travelled}{Circumference\ of\ the\ wheel}$
Percentage and its Application:
Loss = C.P = S.P
The profit or loss percentage can be calculated as $\frac{profit/loss}{cost\ price}$*100
S.P = $\frac{100+profit}{100}$*C.P
S.P = $\frac{100loss}{100}$*C.P
C.P = $\frac{100}{100+profit}$*S.P
C.P = $\frac{100}{100profit}$*S.P
Interest:
When rate of discount is given Discount = $\frac{MP*Rate\ of\ discount}{100}$
Simple Interest = $\frac{PTR}{100}$
where P = Principal , T = Time in years R = Rate of interest per annum
Principal = $\frac{100*S.I}{R*T}$
Rate = $\frac{100*S.I}{P*T}$
Time = $\frac{100*S.I}{P*R}$
Geometric Formula:
Diameter of a circle d = 2r , where r is radius
Circumference of a circle C = 2πr , when radius is given
Relation between circumference and diameter is C = πd
Area:
Solid Figure  Area  
Triangle : 
= $\frac{1}{2}$ bh  b = base,h = height 
Rectangle: 
= l* w Perimeter of Rectangle : 2(l+w) 
l= length,w = width 
Square: 
= s2 Perimeter of square : 4s 
S = length of the side 
Circle: 
= πr^{2}  where r is the radius 
Volume:
Cube: V = S^{3}^{}
Rectangular Prism: V = l*w*h
Cylinder V = πr^{2}h
Rectangular Prism: V = l*w*h
Cylinder V = πr^{2}h
Time:
1 year : 52 weeks
1 week : 7days
1 day: 24 hours
1Hour: 60 minutes
1 minute: 60 seconds
Capacity and volume:
Metric:
1 liter = 1000 milliliters
Customary:
1 gallon = 4 quarts
1 gallon = 128 fluid ounces
1 quart = 2pints
1 pint = 2 cups
1 cup = 8 fluid ounces
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Question:this is not homework i had a math test and everything went PERFECT except i could not get this last question i mean it was hard so i had a spare peice of paper and decided to write it down and maybe later i could see what i did wrong (no i am not planning to change my answer)
but the question is....
Nancy made a cylindrical jewelry holder for her dresser she covered 1 base and the side with silver paper if the holder was 12 cm. tall and 14 cm wide, about how much silver paper did nacy use. ( use pi=3 )
A. 651 cm
B. 500 cm
C. 800 cm
D. 750 cm
the formula for surface area of a cylinder is
S=2B+Ph
i put A.
what do u think it is...
im in acc. math
Answers:your right
Answers:your right
Question:Can anyone help me with my math homework? Don't just give me the answer, explain how you got it. Thanks!
Here's the directions:
________________________________________________
Suppose you roll two dice. Use a chart of possible outcomes to find each probability.
1.) How many outcomes are in the sample space? < (no clue what that means?!)
2.) What is P(6,3) ?
3.) What is P(5,2) ?
4.) What is P(even number, odd number) ? ****
5.) What is P(both numbers are odd) ? ****
__________________________________________
**** = I especially don't know... :(
Answers:The "sample space" is the set of all things that could possibly happen. So, here, the sample space is the set of all possible outcomes from rolling the dice. There are 6 x 6 = 36 outcomes in this particular sample space  try working out why. The probability of an event occurring is the number of different ways that event could happen divided by the number of things that could happen overall. So, if I roll ONE die, the probability of getting an odd number is equal to 3 divided by 6, because there are six ways the die could roll, and only 3 of them are odd numbers (1, 3, and 5). So. P(6, 3) here means "the probability of die one giving a 6, and die two giving a 3, at the same time". Obviously, there is only one way this could happen. And as I said, there are 36 total possible outcomes, so P(6, 3) = 1 divided by 36. You should be able to do the rest on your own..?
Answers:The "sample space" is the set of all things that could possibly happen. So, here, the sample space is the set of all possible outcomes from rolling the dice. There are 6 x 6 = 36 outcomes in this particular sample space  try working out why. The probability of an event occurring is the number of different ways that event could happen divided by the number of things that could happen overall. So, if I roll ONE die, the probability of getting an odd number is equal to 3 divided by 6, because there are six ways the die could roll, and only 3 of them are odd numbers (1, 3, and 5). So. P(6, 3) here means "the probability of die one giving a 6, and die two giving a 3, at the same time". Obviously, there is only one way this could happen. And as I said, there are 36 total possible outcomes, so P(6, 3) = 1 divided by 36. You should be able to do the rest on your own..?
Question:im doing my math homework and stumbled upon a question that i cant figure out at all. i know u can use master product but you can also simplify it somehow but im confused on how to do that.
factor each polynomial completely. check your answer.
4y^8 + 36y^7 + 81y^6
please explain how u simplified it so i can learn from that next time. thanks!!
Answers:The given expression is 4y^8 + 36y^7 + 81y^6 Step 1. Look for any common factor in the exp. You find y^6 common in all terms of the exp. So 4y^8 + 36y^7 + 81y^6 = y^6(4y^2 + 36y + 81) Step 2. After removing the common factor, we have (4y^2 + 36y + 81). The next steps in factorisation is to check for similarity of any identity. ( If none, then go for factoring the mid term into two parts such that coeff 1 : first part :: second part : coeff 3) Here we see that the new first term is (2y)^2 and last term is 9^2. Also mid term is 2*2y*9. Hence (a+b)^2 formula applies. Hence 4y^8 + 36y^7 + 81y^6 = y^6*(2y+9)^2 >>>>>>>>>>Answer
Answers:The given expression is 4y^8 + 36y^7 + 81y^6 Step 1. Look for any common factor in the exp. You find y^6 common in all terms of the exp. So 4y^8 + 36y^7 + 81y^6 = y^6(4y^2 + 36y + 81) Step 2. After removing the common factor, we have (4y^2 + 36y + 81). The next steps in factorisation is to check for similarity of any identity. ( If none, then go for factoring the mid term into two parts such that coeff 1 : first part :: second part : coeff 3) Here we see that the new first term is (2y)^2 and last term is 9^2. Also mid term is 2*2y*9. Hence (a+b)^2 formula applies. Hence 4y^8 + 36y^7 + 81y^6 = y^6*(2y+9)^2 >>>>>>>>>>Answer
Question:So I was learning about probability a few months ago. I basically forgot how to do them which is pathetic of me. I'm reviewing my notes but the thing is, I got a new note book at the time and put all the notes on how to do these problems. I lost that note book a few days later at school _. I'd appreciate if you can kindly explain & help answer these questions. Thank you very much!
9) From an ordinary deck of cards, one card is drawn. What is the probability that the card drawn is a queen and a black card?
5) There are 14 girls and 15 boys in a class. If the teacher calls on two students, what is the probability that they are 2 boys?
7) A bag contains 2 green marbles and 4 blue marbles, and 5 red. If a marble is chosen at random, what is the probability of choosing 2 blue marbles if the first marble is returned to the bag before the second marble is chosen? Oh and one more question,
12 is 75% of what number?
Yeah, I know it's 16 but I'm unsure of how to get the answer. What's the equation for this? Oh nevermind about the details question. I got it hahaha.. .''
Answers:9) there are 52 cards in the deck, 4 of which are Queens. Two of these queens are black. Therefore, the probability of drawing a black queen is 2/52, which equals 1/26 5) (15/29) x (14/28) = 210/812 = .2586 (15/29) is the probability that the first student will be a boy (because 15 out of 29 students are boys). You multiply this by the probability that the second student picked will be a boy (14/28) because there are only 28 students left to choose from because you took out the first student 7) (4/11) x (4/11) = 16/121= .132 This is because the probability of choosing a blue marble on the first try is 4/11, and since you replace the marble, the second probability is the same (4/11). You multiply the 2 probabilities together because of the formula P(A AND B) = P(A) x P(B) which means the probability of A and B BOTH occurring is equal to the probability of A multiplied by the probability of B
Answers:9) there are 52 cards in the deck, 4 of which are Queens. Two of these queens are black. Therefore, the probability of drawing a black queen is 2/52, which equals 1/26 5) (15/29) x (14/28) = 210/812 = .2586 (15/29) is the probability that the first student will be a boy (because 15 out of 29 students are boys). You multiply this by the probability that the second student picked will be a boy (14/28) because there are only 28 students left to choose from because you took out the first student 7) (4/11) x (4/11) = 16/121= .132 This is because the probability of choosing a blue marble on the first try is 4/11, and since you replace the marble, the second probability is the same (4/11). You multiply the 2 probabilities together because of the formula P(A AND B) = P(A) x P(B) which means the probability of A and B BOTH occurring is equal to the probability of A multiplied by the probability of B
From Youtube
PSSA 7th Grade Math :WEBSITE: www.teachertube.com PSSA 7th Grade Math
PSSA 7th Grade Math :WEBSITE: www.teachertube.com PSSA 7th Grade Math