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4th Grade Math Simplifying Expressions

4th Grade Math Simplifying Expressions: 4th grade maths Simplifying expression help students to learn the basics of an algebraic equation. Based on student's capability of knowledge and understandability the topic is brought out in 4th grade.

Simplify Expression Using Orders of operation: The expression is simplified using BODMAS rule.

BODMAS  Means:

B = brackets
o = of                                 (power  and square root of the terms are carried )
d = division                         (operation carried out from left- right )
m = multiplication            (operation carried out from left- right )
a = addition
s = subtraction

Simplifying Expression: Before simplify the expression order of operation to be taken care namely

a)Multiplication and division
b)Addition and subtraction

We have come up with few problems on how to simplify the expression.

     1.   6 + 8 – 8 ÷ 8
           6 + 8 – 1 // Step 1: Multiply and divide from left to right. //
           14 - 1             // Step 2: Add and subtract from left to right  //
           13

      2.  20 ÷ 4 – 6 ÷ 2
            5 – 6 ÷ 2 // divide from left to right. //
            5 – 3        //  subtract from left to right  //
               = 2

       3.  12 ÷ 4 + 5 * 3 – 6
         
       Step 1:  Multiply and divide from left to right
                         3 + 5*3 - 6
                         3 + 15 - 6
            
       Step 2:  Add and subtract from left to right.
                         18 - 6
                         12    // the answer is 12 //

Words Problems: The expression is being brought out with word problem which involves mathematical operation like addition, subtraction, multiplication and subtraction of the term.

   1.  Arun has two pen. One pencil is a inches long. The other pencil is 2 times longer than the first pen and there sum of height is 9 How long is the each  pencil ?
                     Let the two pencils be x  and y.
                     Given first pen x = a …..........(1)
                     y = 2 times longer than x,  y = 2a ….........(2)
                     x + y = 9
                     a + 2a = 9 // assign the value of x and y   //
                           3a = 9 // divide the equation with constant term 3 //
                     
              $\frac{3a}{3}=\frac{9}{3}$   
                     a = 3
                     substitute the value of a in equitation 1 and 2
                     x = 3
                     y = 2*3
                        = 6

          2.  John walked $\frac{4}{8}$ of a mile to his friend’s house, and then $\frac{2}{8}$ of a mile to his house. How  far  did John  walk altogether?

               Given John walked  $\frac{4}{8}$ of a mile to his friend’s house, and then $\frac{2}{8}$ of a mile to his house.

               $\frac{4}{8}$, $\frac{2}{8}$
               
                The denominator of the term remains constant we need not to take LCM. Add the two terms.

                 $\frac{4}{8}$ + $\frac{2}{8}$
                   = $\frac{6}{8}$     // reduce to the lowest term  //
                   = $\frac{3}{4}$